Yahoo Answers: Answers and Comments for A jet flew 140 mi on a course of 196 degrees and then 120 mi on a course of 106 degrees then the jet return***? [Mathematics]
Copyright © Yahoo! Inc. All rights reserved.
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
From LJ
enPH
Sun, 28 Aug 2011 04:32:33 +0000
3
Yahoo Answers: Answers and Comments for A jet flew 140 mi on a course of 196 degrees and then 120 mi on a course of 106 degrees then the jet return***? [Mathematics]
292
38
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
https://s.yimg.com/zz/combo?images/emaillogoph.png

From Mike G: Course change = 196106 = 90 degrees
So we ha...
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
Sun, 28 Aug 2011 11:51:14 +0000
Course change = 196106 = 90 degrees
So we have a right angled triangle
140^2+120^2=D^2
D = 184.4 miles
Total distance =
140+120+184.4 =
444.4 miles

From ?: 184.35 mi + 140 mi + 120 mi = 444.35 miles.
P...
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
https://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
Sun, 28 Aug 2011 11:48:28 +0000
184.35 mi + 140 mi + 120 mi = 444.35 miles.
Proof:
The angle in which it turned = 196106 = 90.
Therefore, it is a right angle.
The shortest route is by turning towards left or right and then traveling towards the starting point.
The distance can be found by using the formula of Pythagoras (i.e., Pythagorean triplet).
The theorem is:
a^2+b^2=c^2.
if it is a right angle, where c is the longest line.
Here,
a=140
b=120
a^2=19600
b^2=14400
a^2+b^2=34000
c=the distance
c^2=34000
c=√34000
c=184.35
total distance=140+120+184.35