The figure below shows part of the graph of a sine wave. Which of the following equations describes the sine wave? thanks ?

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3 Answers

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  • 2 months ago
    Favorite Answer

    (D) y = 2(sin(x/2)) + 1

    Edit - reasoning explained (if required)

    1° period is 4pi so the argument of sine is divided by 2

    2° amplitude between min (y= -1) and max (y=+3) is 4 while sine has amplitude 2 (from -1 to +1) --> value of sine is multiplied by 2

    3° the function is oscillating around y=1 ----> the sinusoid is shifted up by 1 unit., so there must be "+1" term included

    Solution (D) fits in

    Check:

    x=0 ----> y(0) = 2(sin(0/2)) + 1 = 1

    x = pi --> y(pi) = 2(sin(pi/2)) + 1 = 3

    x = 2pi -->y(2pi) = 2(sin(pi)) + 1 = 1

    x = 3pi -->y(3pi/2) = 2(sin(3pi/2)) + 1 = -1

    x = 4pi -->y(4pi) = 2(sin(2pi)) + 1 = 0

    ok

  • Vaman
    Lv 7
    2 months ago

    Just check, y=1 when x=0. This gives B, C, and D are valid solutions. A is not the sine wave that represents the graph. But at x=pi, y=3. This possible for D only. D is represented in the graph.

  • ?
    Lv 7
    2 months ago

    // y = A sin [B(x+C)] + D

    // where A = amplitude

    //            period = 2π/B ⇒ B = 2π/period

    //            C = phase shift

    //            D = vertical shift

    BASE function......................y₀ = sin x

    VERTICAL STRETCH

    by 2 units (A = 2) ................y₁ = 2 sin x

    HORIZONTAL STRETCH

    by 2 units

    (Period = 4π ⇒ B = ¹⁄₂)........y₂ =  2 sin ˣ⁄₂

    No phase shift (C=0)...........y₃ =  2 sin ˣ⁄₂

    VERTICAL SHIFT by

    1 unit (D = 1)........................y₄ = 2 sin ˣ⁄₂  + 1

    So, the equation of the graph is

                   y = 2 sin ˣ⁄₂  + 1  ................ANS (Option D)

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