What's the answer to this problem? ?
there's a picture attached, and this is calculus

1 Answer
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- JeremyLv 63 months agoFavorite Answer
f(x, y) = 5 * ln(x^2 + y^2)
f_x = [5/(x^2 + y^2)] * 2x = (10x)/(x^2 + y^2)
f_xy = (-10x * 2y)/(x^2 + y^2)^2 = (-20xy)/(x^2 + y^2)^2
f_y = [5/(x^2 + y^2)] * 2y = (10y)/(x^2 + y^2)
f_yx = (-10y * 2x)/(x^2 + y^2)^2 = (-20xy)/(x^2 + y^2)^2
Hence: f_xy = f_yx
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