hey someone please help me out with this question thanks!
What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 82.0 g of HCl and aqueous phosphorous acid (H3PO3)?
- anonymousLv 71 month ago
balanced reaction equation:
PCl₃(ℓ) + 3 H₂O(ℓ) ⟶ 3 HCl(aq) + H₃PO₃(aq)
theoretical yield in grams of HCl from 200. g PCl₃ and excess water:
(200. g PCl₃) x (1 mole PCl₃ / 137.33 g PCl₃) x (3 moles HCl / 1 mole PCl₃) x
(36.46 g HCl / 1 mole HCl)
= 159.30 g HCl
= (actual yield / theoretical yield) x 100%
= (82.0 g / 159.30 g) x 100%
= 51.5% …… to 3 sig figs