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Anonymous asked in Education & ReferenceHomework Help · 1 month ago

chem help!?

hey someone please help me out with this question thanks!

What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 82.0 g of HCl and aqueous phosphorous acid (H3PO3)?

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  • 1 month ago

    balanced reaction equation:

    PCl₃(ℓ) + 3 H₂O(ℓ) ⟶ 3 HCl(aq) + H₃PO₃(aq)

    theoretical yield in grams of HCl from 200. g PCl₃ and excess water:

    (200. g PCl₃) x (1 mole PCl₃ / 137.33 g PCl₃) x (3 moles HCl / 1 mole PCl₃) x

    (36.46 g HCl / 1 mole HCl)

    = 159.30 g HCl

    percent yield

    = (actual yield / theoretical yield) x 100%

    = (82.0 g / 159.30 g) x 100%

    = 51.5% …… to 3 sig figs

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