Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

PLEASE ANSWER QUICKLY URGENT!!!!!!!!!?

The sum of three integers is 208. The two smaller are consecutive integers and the two larger are consecutive odd integers. Find the smallest number.

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  • 1 month ago

    Sounds like LIBERAL JARGON #GodBless

  • 1 month ago

    Let two smaller consecutive intgers numbers=x,x+1

    Let larger odd consecutive intergers numbers=x+1,x+3

    According question x+x+1+x+3=208

    3x=208-4

    3x=204

    x=204÷3

    x=68

    x+1=69

    x+3=71

    So these three numbers=68,69,71

  • 1 month ago

    Hi

    Let, the two larger consecutive odd integers be 2n + 1, 2n + 3

    The smallest number is then 2n

    6n + 4 = 208

    The smallest number is 204/3 = 68

    68 + 69 + 71 = 208

  • oubaas
    Lv 7
    1 month ago

    a+b+c = 208 

    a is even, b = a+1 is odd and a+b is odd 

    c = b+2

    c = a+3

    3a+4 = 208

    a = 204/3 = 68

    b = 69

    c = 71 

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  • Ian H
    Lv 7
    1 month ago

    Let the two larger consecutive odd integers be 2n + 1, 2n + 3

    The smallest number is then 2n

    6n + 4 = 208

    The smallest number is 204/3 = 68

    68 + 69 + 71 = 208

  • 1 month ago

    Let the Integers by

    n , n+1 & n+3

    'n' & 'n+1' are consecutive

    'n+1' & 'n + 3' are consecutive odd . 

    Hence their sum is 

    n + ( n+ 1 + (n+ 3) = 208

    Adding 

    3n + 4 = 208 

    3n = 204 

    n = 68  The smallest number. 

    The other being '69' & '71' 

  • 1 month ago

    Whats up anonymous you big red ****, lets get mathy, as I always say at the start of my math lessons. As you know, of course, an integer is the sum of the fraction between two sides of a rhomboid. So, applying this basic principle to this fraction, we can see that x = rhomboid, y = 208, ☺ = 34, and the amount of consectuvie integers = 4. So, it's simple really, x Xx X x = y xX Xxx + (☺☺ looktheyre like a little couple hehe)* 56

    what you really wanna be looking out for here is that answer doesn't protrude more than 5/8ths of an inch off the page, otherwise that would be disgusting. With the equation laid out above as I did for you, you should get it in no time. Id tell you the answer, but I don't wanna do all your homework for you! hehe

    Source(s): math teacher for 29 years, father for 18, gamer for 2, meth & math addicted leftist
  • 1 month ago

    I would ignore that the second two integers are odd, except that it means they differ by two.  I can check for oddness, later.

    If the smallest integer is a, then the next integer is consecutive, so it's a+1.  And the next integer after that is a+3.

    a + a+1 + a+3 = 208

    3a + 4 = 208

    3a = 204

    a = 68

    quick check, yes, the second and third integers are odd

    ---

    Alternate thinking, not faster in this case

    The numbers are all almost the same, so divide 208 by 3 as a guess for the middle one.  210 is the closest thing I can easily divide by 3, which would give 70 as the middle one.  But 70 is even, 210 is too much, so I'll take it down a notch and guess 69 for the middle one.  (If 210 was too little, I'd try 71 as the middle one.).  Check the guess.

  • 1 month ago

    The sum of three integers is 208. 

     The two smaller are consecutive integers and 

     the two larger are consecutive odd integers. 

     Find the smallest number. 

     x + (x + 1) + (x + 3) = 208

     The smallest number is 68

  • 1 month ago

    The sum of three integers is 208:

    x + y + z = 208

    The two smaller are consecutive integers:

    y = x + 1

    And the two larger are consecutive odd integers:

    z = y + 2  (if y is odd, then the next odd is (y + 2))

    We now have a system of three equaitons and three unknowns.  The way I set up the equations:

    x < y < z

    The smallest number is then "x".

    Let's substitute the last equation in terms of y for z in the first equation, then simplify:

    x + y + z = 208

    x + y + y + 2 = 208

    x + 2y + 2 = 208

    x + 2y = 206

    Now we can substitute the expression from the second equation into the above and solve for x:

    x + 2(x + 1) = 206

    x + 2x + 2 = 206

    3x + 2 = 206

    3x = 204

    x = 68

    The smallest number is 68.

    If you want to solve for y and z, substistute into the other equations and solve and you should get:

    y = 69 and z = 71

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