Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

What is the solution of the equation 5e^(x-3)=4 ?

5 Answers

Relevance
  • 2 months ago
    Favorite Answer

    5e^(x - 3) = 4 

    Divide both sides by 5

    e^(x - 3) = .8

    Take the ln of both sides

    x - 3 = ln .8

    add 3 to both sides

    x = ln .8 + 3

    x ≈ 2.77685644868579 <––––––

  • Philip
    Lv 6
    2 months ago

    5e^(x-3) = 4, ie., e^(x-3) = (4/5) = 0.8. Take ln of both sides to get x-3 = ln(0.8).

    Then x = 3+ ln(0.8) = 3-0.2231435513 = 2.776856449.

  • 2 months ago

    5e^(x - 3) = 4

    I would start by dividing both sides by 5:

    e^(x - 3) = 4/5

    Natural log of both sides:

    x - 3 = ln(4/5)

    Add 3 to both sides:

    x = 3 + ln(4/5)

    or:

    x = 3 + ln(4) - ln(5)

  • ?
    Lv 7
    2 months ago

    5 eˣ⁻³ = 4

    ln 5 + (x-3) ln e = ln 4

    ln 5 + (x-3) (1) = ln 4

    x - 3 = ln 4 - ln 5

    x = ln 4 - ln 5 + 3

    x = 2.77686................ANS (rounded)

  • How do you think about the answers? You can sign in to vote the answer.
  • 2 months ago

    take logs of both sides......ln5+(x-3)ln(e)=ln 4, but ln(e)=1, so x-3 = ln 4 - lin 5, so x= 3+ln(4/5)

Still have questions? Get your answers by asking now.