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# Find an equation of the line passing through the pair of points (2,3) and (-6,-6). Write the equation in the form Ax+By=C.?

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- PhilipLv 61 month ago
Line L passes through P(2,3) & Q(-6,-6). Let R(x,y) be any other point on L. Then

slope PR = slope QP, ie., (y-3)/(x-2) = (3+6)/(2+6) = (9/8). Then 8(y-3) = 9(x-2), ie.,

9x-8y = 18-24, ie., 9x-8y =-6, the eqn of L.

- KrishnamurthyLv 71 month ago
The equation of the line passing through the pair of points (2,3) and (-6,-6):

- lenpol7Lv 71 month ago
y- - 6 = [(-6-3)/(-6-2)](x - -6)

y + 6 = [-9/-8](x + 6)

y + 6 = [9/8](x + 6)

8y + 48 = 9x + 54

9x - 8y = -6

- Φ² = Φ+1Lv 71 month ago
The line through the points (x₁,y₁) and (x₂,y₂) is (y₁-y₂)x - (x₁-x₂)y = y₁×x₂ - x₁×y₂.

Here this is (3--6)x - (2--6)y = 3×-6 - 2×-6 which simplifies to 9x+8y=-6.

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- PopeLv 71 month ago
(-6 - 3)(x - 2) - (-6 - 2)(y - 3) = 0

-9(x - 2) + 8(y - 3) = 0

-9x + 18 + 8y - 24 = 0

9x - 8y = -6

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