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# How to find the vertical asymptote using limits of f(x)= (2x+3)/sqrt(x^2-2x-3)?

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- 1 month agoFavorite Answer
x^2 - 2x - 3 = 0

x = (2 +/- sqrt(4 + 12)) / 2

x = (2 +/- 4) / 2

x = 1 +/- 2

x = -1 , 3

When x = -1 and when x = 3, the function is undefined. No need for limits.

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