can you please help with this question?
A basketball player makes a long pass to another player. The path of the ball can be modeled by y = −0.2x² + 2.4x + 2, where x is the horizontal distance from the player and y is the height of the ball above the court, both in meters. Determine the maximum height of the ball.
- 1 month ago
Hi, I'll give it a try.
Max height will be when dy/dx=0 (i.e. differential)
So dy/dx= 2*(-0.2)x + 2.4 (the 2 disappears as d/dx of a constant is 0)
so plug x=6 into equation and see what y is
ok y=-0.2* (6^2)+2.4 *(6) +2= 9.2m
This is the same answer that Alex (the first answerer) would've have got.
- alexLv 71 month ago
max or min value is f(-b/(2a))