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- Demiurge42Lv 71 month ago
I think they may have a typo in the question. It should be the limit as x approaches 0 not 1.

lim [e^x-1] / x

x→0

Another good hint would be to rewrite 1 as e^0.

lim [e^x-e^0] / (x-0)

x→0

This would be the derivative of f(x) = e^x at x = 0.

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- ted sLv 71 month ago
if you don't know L'Hospital's methods the go to ' wikipedia.org '

and read...then you should see the answer to the query is 1...by just looking at it

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