Amandeep asked in Science & MathematicsMathematics · 10 months ago

# Twice the total of two numbers is 60. The larger exceeds twice the smaller by 12. Find the numbers?

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• 10 months ago

2(A+B)=60. A+B=30. 30/2=15 15+6=21, 15-6=9

9+21=30 21-9=12. 2*(9+21)=60.

9 & 21

• oubaas
Lv 7
10 months ago

2(a+b) = 60

a = 2b+12

4b+24+2b = 60

6b = 60-24 = 36

b = 6 ; a = 12+12 = 24

• 10 months ago

2x + 2y = 60

x = 2y + 12

2x - 4y = 24

6y = 36

y = 6

x = 24

The two numbers are 24 and 6.

• 10 months ago

I gotchu fam. I found your numbers. Hope this helps!

• sepia
Lv 7
10 months ago

2(x + y) = 60

x = 2y + 12

2x + 2y = 60

2x - 4y = 24

6y = 36

y = 6

x = 24

The two numbers are 24 and 6.

• 10 months ago

60/2=s+2s+12

18=3s

s=6

• 10 months ago

Let L be the larger.

Let S be the smaller.

Twice the total of two numbers is 60:

2(L + S) = 60

The larger exceeds twice the smaller by 12:

L = 2S + 12

Let's substitute in for L into the first equation:

2(2S + 12 + S) = 60

2(3S + 12) = 60

Divide both sides by 2

3S + 12 = 30

3S = 30 - 12

3S = 18

S = 18/3

S = 6

Then figure out the larger:

L = 2S + 12

L = 2(6) + 12

L = 24

The smaller number is 6 and the larger number is 24.

• 10 months ago

This is a classic "simultaneous equations" problem. You need to set up two equations that describe the two clues given.

A = the larger number, B = the smaller number.

2(A + B) = 60

A + 12 = 2B

Plug and chug.

• Kaz
Lv 7
10 months ago

6 & 24 .

• Anonymous
10 months ago

You don't need to tell us. Go ahead and do it.