Anonymous

# physics issues?

The pattern below is detected on a screen 10π away from some unknown

number of slits. If the wavelength of the light is 500ππ, the distance between

primary maxima is 1ππ, and the distance between primary and secondary

maxima is . 5ππ, whatβs the distance between the slits? You may use the small

angle approximation.

A) 2.5ππ

B) 5ππ

C) 10ππ

D) 1ππ

E) 5πm

### 1 Answer

Relevance

- Anonymous4 weeks ago
Answer is distance between first secondary and fourth secondary maximum, thus is evaluated as 2.5mm.

Simple.

Formula is (0.5)mm * (6).

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