The pattern below is detected on a screen 10𝑚 away from some unknown
number of slits. If the wavelength of the light is 500𝑛𝑚, the distance between
primary maxima is 1𝑚𝑚, and the distance between primary and secondary
maxima is . 5𝑚𝑚, what’s the distance between the slits? You may use the small
- Anonymous8 months ago
Answer is distance between first secondary and fourth secondary maximum, thus is evaluated as 2.5mm.
Formula is (0.5)mm * (6).