# two more than a certain number is 15 less than the product of 7/8 and the number?

### 7 Answers

- King LeoLv 79 months agoFavorite Answer
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let the number = x

two more than the number = ( x + 2 )

product of the number and ⅞ = ⅞x

if you add 15 to ( x + 2 ) the result will ⅞x

( x + 2 ) + 15 = ⅞x

8x + 16 + 120 = 7x

x = -136

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- lenpol7Lv 79 months ago
Let the number be 'n'

Hence n + 2 = 15 + (7n/8)

n - 13 = 7n/ 8

8n - 104 = 7n

n = 104

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- sepiaLv 79 months ago
Two more than a certain number is 15 less than the product of 7/8 and the number:

n + 2 = 7/8 n - 15

1/8 n = -17

n = -136

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- RRLv 79 months ago
Two more than a certain number

x + 2

...is 15 less than the product of 7/8 and the number?

x + 2 = (7x/8) - 15

multiply by 8 to eliminate the fraction

8x + 16 = 7x - 120

x = -136

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- KrishnamurthyLv 79 months ago
Two more than a certain number is 15 less than the product of 7/8 and the number:

n + 2 = 7n/8 - 15

8n + 16 = 7n - 120

n = -136

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- 9 months ago
n + 2 = (7/8) * n - 15

n + 17 = (7/8) * n

(1/8) * n + 17 = 0

n + 136 = 0

n = -136

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