el pepe asked in Science & MathematicsMathematics · 9 months ago

# two more than a certain number is 15 less than the product of 7/8 and the number?

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• 9 months ago

.

let the number = x

two more than the number = ( x + 2 )

product of the number and ⅞ = ⅞x

if you add 15 to ( x + 2 ) the result will ⅞x

( x + 2 ) + 15 = ⅞x

8x + 16 + 120 = 7x

x = -136

• 9 months ago

Let the number be 'n'

Hence n + 2 = 15 + (7n/8)

n - 13 = 7n/ 8

8n - 104 = 7n

n = 104

• David
Lv 7
9 months ago

The value of the unknown number is -136

• sepia
Lv 7
9 months ago

Two more than a certain number is 15 less than the product of 7/8 and the number:

n + 2 = 7/8 n - 15

1/8 n = -17

n = -136

• RR
Lv 7
9 months ago

Two more than a certain number

x + 2

...is 15 less than the product of 7/8 and the number?

x + 2 = (7x/8) - 15

multiply by 8 to eliminate the fraction

8x + 16 = 7x - 120

x = -136

• 9 months ago

Two more than a certain number is 15 less than the product of 7/8 and the number:

n + 2 = 7n/8 - 15

8n + 16 = 7n - 120

n = -136

• 9 months ago

n + 2 = (7/8) * n - 15

n + 17 = (7/8) * n

(1/8) * n + 17 = 0

n + 136 = 0

n = -136