Given the function f(x)=c, where is c is some constant. Show that f’(x)=0 Hint: by limit definition?

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  • david
    Lv 7
    9 months ago
    Favorite Answer

    f' = lim (h-->0) [ (c) - (c) ] /h

    = lim (h-->0) 0/h

    = lim (h-->0) 0

    f' = 0 <<< answer

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  • 9 months ago

    f(x) = Cx^0

    Remember x^0 = 1

    Hence

    f'(x) = 0(C)x^(0-1)

    f'(x) = 0 Because anything multiplied by zero (0) = zero(0) .

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  • Anonymous
    9 months ago

    You know how in the numerator of the derivative expression you see f(x)-f(c)? Or f(x+h)-f(x) depending on which definition you learned? Well...... What is f of any number you could ever plug in?

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