Find the probability of at most one tail appearing on two tosses of a coin. (Round your answer to two decimal places.)?

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  • 6 months ago

    The probability of "at most 1 tail" equals 1 - (the probability of more than 1 tail). The probability of two tails (the only possibility more than 1) is 0.25.

    Thus, the probability of at most one tail is 0.75

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  • 6 months ago

    There are four possible outcomes:

    heads then heads: 0 tails

    heads then tails: 1 tail

    tails then heads: 1 tail

    tails then tails: 2 tails

    Of those, the first three match the criteria "at most one tail."

    So the answer is 3/4 = 0.75 = 75%

    • Puzzling
      Lv 7
      6 months agoReport

      Slight typo in the fraction at the end (should be 3/4), but you have the correct decimal/percentage.

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  • Anonymous
    6 months ago

    Well see this one is really easy because you can just list out the probabilities since there aren't that many:

    HH - Heads on both tosses

    TT - Tails on both tosses

    HT - Heads, then tails on the next toss

    TH - Tails, then heads on the next toss

    HH, TT, and HT have at most one tails so that's three of the four (3/4) or 75%

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  • Anonymous
    6 months ago

    The answer is 0.01.

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