The maximum amount of calcium hydroxide that will dissolve in a 0.103 M calcium acetate solution is ---- M?

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  • 2 years ago

    Dissolving equilibrium: Ca(OH)2(s) <--> Ca2+(aq) + 2 OH-(aq)

    Ksp = 6.5X10^-6 = [Ca2+][OH-]^2

    Let x = molar solubility of Ca(OH)2.. Then, 0.103 + x = [Ca2+] and [OH-] = 2x. Assume x is small compared to 0.103 and can be ignored. So,

    6.5X10^-6 = 0.103 (2x)^2

    x = 4.0X10^-3 = M solubility of Ca(OH)2 in 0.103 M calcium acetate.

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