The maximum amount of calcium hydroxide that will dissolve in a 0.103 M calcium acetate solution is ---- M?
- hcbiochemLv 72 years ago
Dissolving equilibrium: Ca(OH)2(s) <--> Ca2+(aq) + 2 OH-(aq)
Ksp = 6.5X10^-6 = [Ca2+][OH-]^2
Let x = molar solubility of Ca(OH)2.. Then, 0.103 + x = [Ca2+] and [OH-] = 2x. Assume x is small compared to 0.103 and can be ignored. So,
6.5X10^-6 = 0.103 (2x)^2
x = 4.0X10^-3 = M solubility of Ca(OH)2 in 0.103 M calcium acetate.