# The maximum amount of silver chromate that will dissolve in a 0.241 M potassium chromate solution is M.?

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- hcbiochemLv 72 years ago
My text lists Ksp for Ag2CrO4 as 1.2X10^-12

Solution equilibrium:

Ag2CrO4(s) <--> 2 Ag+(aq) + CrO42-(aq)

Ksp = 1.2X10^-12 = [Ag+]^2 [CrO42-]

Let 2x = [Ag+] and 0.241 + x = [CrO42-]. Assume that x is << 0.241 and can be ignored. So

1.2X10^-12 = (2x)^2 (0.241)

x = 1.1X10^-6 M = solubility of Ag2CrO4 in 0.241 M K2CrO4

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