# Alvin is 11 years older than Elga. The sum of their ages is 71 . What is Elga's age?

math!

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• ley x - Alvis age

let y Elgas age

x = y + 11 eq1

x + y = 71 eq2

plug in eq1 to eq2

y + 11 + y = 71

2y + 11 = 71

2y = 71 - 11

2y = 60

y =30 <----------Elgas age

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• A + E = 71

A = E + 11

Hence

E = A - 11

Substitute

A + (A - 11) = 71

2A = 82

A = 42

E = 31

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• Let A and E be Alvin's and Elga's ages respectively.

A= E + 11

A + E = 71

A-E=11

2A=82

A=41

41+E=71

E=30

Elga is 30.

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• I figured it out in my head in less than 10 seconds. If I can do it, you can do it.

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• If you took away the 11 year difference they would be the same age and the sum would be 60. Hence Elga is half that or 30.

Elga is 30 (and Alvin is 41)

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• A + E = 71 and A - E = 11 so E = (71 - 11)/2 = 30

Elga is 30 years old.

• Thank you for asking this question. Now that over a month has passed, can you please award the Best Answer to whichever answer you find most deserving?

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• Elga = x

Alvin = x+11

x+x+11 = 71

2x+11 = 71

2x = 71-11

2x = 60

x = 60÷2

x = 30

• You idiot - you'e showing off and at the same time you're helping someone cheat on their homework. What's wrong with you?

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• Alvin is 11 years older than Elga.

The sum of their ages is 71.

A + E = 71

A - E = 11

A = 41, E = 30

Elga is 30 years old.

• You idiot - you'e showing off and at the same time you're helping someone cheat on their homework. What's wrong with you?

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• Elga is 30.

Thumbs down? Are you stupid?

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• A-E = 11

A+E = 71

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