# Given that sin(B)=1/5 and AD=BD , find sin(∠ADC). ???? help me please?

please show me steps

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- mizooLv 73 years ago
Angle ADC = angle A + angle B (both sides are equal to 180 - angle ADB)

Angle ADC = 2 angle B

sin ADC = sin (2B)

sin (2B) = 2sin B cos B

sin (2B) = 2(1/5) sqrt(1 - 1/5^2)

sin (2B) = 2 * 1/5 * sqrt24 / 5

sin (2B) = 2 * 1/5 * 2(sqrt 6) / 5

sin (2B) = 4sqrt 6/25

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