Perpendicular lines have opposite-reciprocal slopes. So if we find the slope of the given line we can find the slope of the line in question. Put the equation into slope-intercept form to determine that slope:

10y + 3x = -2

10y = -3x - 2

y = (-3/10)x - (1/5)

So the slope is -3/10, so the perpendicular slope is 10/3.

We want the equation of the line with that slope and passes through the given point. So we know the slope, x, and y values, so we can solve for the unknown, the intercept:

y = mx + b

2 = (10/3) * 8 + b

2 = 80/3 + b

2 - 80/3 = b

6/3 - 80/3 = b

b = -74/3

So the equation of the line in slope-intercept form is:

y = (10/3)x - 74/3

If you want the standard form of the equation, multiply both sides by 3 and move the x term to the left side:

3y = 10x - 74

-10x + 3y = -74

we need x's coefficient to be positive, so multiply both sides by -1:

10x - 3y = 74

So those are two equations for the line in question. If this helped, please give best answer. Thanks.