LJ asked in Science & MathematicsMathematics · 9 years ago

A jet flew 140 mi on a course of 196 degrees and then 120 mi on a course of 106 degrees then the jet return***?

***to its starting point via the shortest route possible. Find the total distance that the jet traveled.

tnx to all who will answers

2 Answers

Relevance
  • 9 years ago
    Favorite Answer

    184.35 mi + 140 mi + 120 mi = 444.35 miles.

    Proof:

    The angle in which it turned = 196-106 = 90.

    Therefore, it is a right angle.

    The shortest route is by turning towards left or right and then traveling towards the starting point.

    The distance can be found by using the formula of Pythagoras (i.e., Pythagorean triplet).

    The theorem is:

    a^2+b^2=c^2.

    if it is a right angle, where c is the longest line.

    Here,

    a=140

    b=120

    a^2=19600

    b^2=14400

    a^2+b^2=34000

    c=the distance

    c^2=34000

    c=√34000

    c=184.35

    total distance=140+120+184.35

    • Login to reply the answers
  • Mike G
    Lv 7
    9 years ago

    Course change = 196-106 = 90 degrees

    So we have a right angled triangle

    140^2+120^2=D^2

    D = 184.4 miles

    Total distance =

    140+120+184.4 =

    444.4 miles

    • Login to reply the answers
Still have questions? Get your answers by asking now.