# A jet flew 140 mi on a course of 196 degrees and then 120 mi on a course of 106 degrees then the jet return***?

***to its starting point via the shortest route possible. Find the total distance that the jet traveled.

tnx to all who will answers

### 2 Answers

- 9 years agoFavorite Answer
184.35 mi + 140 mi + 120 mi = 444.35 miles.

Proof:

The angle in which it turned = 196-106 = 90.

Therefore, it is a right angle.

The shortest route is by turning towards left or right and then traveling towards the starting point.

The distance can be found by using the formula of Pythagoras (i.e., Pythagorean triplet).

The theorem is:

a^2+b^2=c^2.

if it is a right angle, where c is the longest line.

Here,

a=140

b=120

a^2=19600

b^2=14400

a^2+b^2=34000

c=the distance

c^2=34000

c=√34000

c=184.35

total distance=140+120+184.35

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- Mike GLv 79 years ago
Course change = 196-106 = 90 degrees

So we have a right angled triangle

140^2+120^2=D^2

D = 184.4 miles

Total distance =

140+120+184.4 =

444.4 miles

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