Best answer:
In the extreme case, all 16 that use laptops could be completely inside the set of students who use desktop computers. In other words, the maximum who use both is 16.
As for the minimum, we can't have the two sets being disjoint (no overlap) because 16 + 38 = 54. That means there has to be an overlap of at...
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Best answer: In the extreme case, all 16 that use laptops could be completely inside the set of students who use desktop computers. In other words, the maximum who use both is 16.
As for the minimum, we can't have the two sets being disjoint (no overlap) because 16 + 38 = 54. That means there has to be an overlap of at least 4 students that use both a laptop and a desktop computer.
Answer:
Minimum of 4 students
Maximum of 16 students
Update:
If it helps, imagine you have 16 labels that say "laptop" and 38 labels that say "desktop" and you have 50 students.
You could give a "laptop" and a "desktop" label to the same 16 students. That's the maximum you could have --> 16 maximum.
(The remaining 22 "desktop" labels would go to any of the remaining students)
16 (both), 22 (just desktop), 12 (no computer)
And for the other way, you could give all the "laptop" labels to 16 students which leaves 34 students. You could give them 34 of the "desktop" labels but you'd have to give 4 "desktop" labels to those students that already have a "laptop" label. That's the minimum you could have with both --> 4 minimum
4 (both), 34 (just desktop), 12 (just laptop)