• Finding coefficients for cubic function?

    Best answer: To show how the conclusion is erroneous, suppose A = 0, B = 0, C = 0, and D = 1234. Or suppose that A = 0, B = 0, C = 123, D = 4. In fact, the f(10) = 1234 could go with ANY choice of A, B, and C ... leaving only D to be determined! For instance, what if A = B = C = 1. Then f(10) = 1110 + D, and D would be... show more
    Best answer: To show how the conclusion is erroneous, suppose
    A = 0, B = 0, C = 0, and D = 1234.
    Or suppose that A = 0, B = 0, C = 123, D = 4.
    In fact, the f(10) = 1234 could go with ANY choice of A, B, and C ... leaving only D to be determined!

    For instance, what if A = B = C = 1. Then
    f(10) = 1110 + D, and D would be 124.

    I could go on forever, but I hope you get the picture.
    6 answers · 15 hours ago
  • Help with simplifying questions, please?

    When simplified 2x+9-4a+4 = 2x-4a+13 My answer was 2x + 13 - 4a. My question is, why in the correct answer must the 13 be at the end? How do you simplify 6(x+y)+2(2x+y)?
    When simplified 2x+9-4a+4 = 2x-4a+13 My answer was 2x + 13 - 4a. My question is, why in the correct answer must the 13 be at the end? How do you simplify 6(x+y)+2(2x+y)?
    7 answers · 16 hours ago
  • Impossible Calculus Problem?

    Best answer: Points given are (65,20) & (66,17) so slope = -3 y - 20 = -3(x-65) where y = bushels/tree and x = number of trees/acre y = -3x + 215 T = total yield/acre = xy = -3x^2+215x dT/dx = -6x + 215 = 0 for maximum x = 215/6 = 35.83 trees/acre Answer 36 to the nearest whole number See my... show more
    Best answer: Points given are (65,20) & (66,17) so slope = -3
    y - 20 = -3(x-65) where y = bushels/tree and x = number of trees/acre
    y = -3x + 215
    T = total yield/acre = xy = -3x^2+215x
    dT/dx = -6x + 215 = 0 for maximum
    x = 215/6 = 35.83 trees/acre
    Answer 36 to the nearest whole number
    See my graph
    https://www.desmos.com/calculator/vxrhir...
    7 answers · 1 day ago
  • Significant figures question?

    Best answer: Your answer is correct but they probably want a less accurate answer rounded to 3 significant digits.
    (1.22+3.655)*10^5 = 4.875*10^5
    = 487,500
    ≈ 488,000 (rounded to 3 significant digits)
    Best answer: Your answer is correct but they probably want a less accurate answer rounded to 3 significant digits.
    (1.22+3.655)*10^5 = 4.875*10^5
    = 487,500
    ≈ 488,000 (rounded to 3 significant digits)
    7 answers · 1 day ago
  • Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function? PLeaseee?

    Best answer: h(t) = -16t^2 + v₀t + h₀ Where: h = the height of the object at any given point in time (in ft) t = time the object is in motion (in sec) h₀ = the initial height (in ft) v₀ = the initial velocity (in ft/sec) If v₀ < 0, the object was propelled downward v₀ = 0, the ball was dropped from rest with no... show more
    Best answer: h(t) = -16t^2 + v₀t + h₀

    Where:

    h = the height of the object at any given point in time (in ft)
    t = time the object is in motion (in sec)
    h₀ = the initial height (in ft)
    v₀ = the initial velocity (in ft/sec)
    If v₀ < 0, the object was propelled downward
    v₀ = 0, the ball was dropped from rest with no initial velocity
    v₀ > 0, the ball was propelled upward

    So in this case we have:

    h(t) = -16t^2 + 37t + 6

    v₀ = 37 ft/sec
    h₀ = 6 ft

    The first derivative of position, h(t) in this case is the velocity:

    v(t) = dh/dt = -32t + 37

    v(3.2) = -32 * 3.2 + 37 = - 65.4 ft/sec => the negative sign is the direction of velocity which is downward

    The above makes D) => the correct choice

    however he ball will hit the ground when the height is zero we can find the time that takes place:

    -16t^2 + 37t + 6 = 0
    using the quadratic formula the approximated times are:
    t ≈ - 0.15 , 2.5 sec => disregarding the negative time, thus the ball hits the ground at t = 2.5 sec, which means at t = 3.2 sec, the ball should be resting on the ground so there is either an error or we are missing some more information
    6 answers · 4 days ago
  • HELP FAST PLEASE! Which statement describes whether a right triangle can be formed using one side length from each of these squares?

    HELP FAST PLEASE! Which statement describes whether a right triangle can be formed using one side length from each of these squares?

    A) Yes, a right triangle can be formed because the sum of the areas of the two smaller squares does not equal the area of the largest square. B) Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square. C) No, a right triangle cannot be... show more
    A) Yes, a right triangle can be formed because the sum of the areas of the two smaller squares does not equal the area of the largest square. B) Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square. C) No, a right triangle cannot be formed because the sum of the areas of the two smaller squares does not equal the area of the largest square. D) No, a right triangle cannot be formed because the sum of the areas of the two smaller squares equals the area of the largest square.
    7 answers · 2 days ago
  • What is 1 third of 2.5 litres of paint?

    20 answers · 6 days ago
  • N/8+56-20=40?

    7 answers · 2 days ago
  • How many ways can 5 cards fit into 5 envelopes?

    Best answer: permutations(5,5) total is 5*4*3*2*1 = 120 as long as 1 card in each envelope and order does matter math is fun explains why we multiply data Permutations without repetition (n=5, r=5) Using Items: 1,2,3,4,5 List has 120... show more
    Best answer: permutations(5,5)
    total is 5*4*3*2*1 = 120
    as long as 1 card in each envelope and order does matter

    math is fun explains why we multiply

    data
    Permutations without repetition (n=5, r=5)
    Using Items: 1,2,3,4,5

    List has 120 entries.
    1,2,3,4,5
    1,2,3,5,4
    1,2,4,3,5
    1,2,4,5,3
    1,2,5,3,4
    1,2,5,4,3
    1,3,2,4,5
    1,3,2,5,4
    1,3,4,2,5
    1,3,4,5,2
    1,3,5,2,4
    1,3,5,4,2
    1,4,2,3,5
    1,4,2,5,3
    1,4,3,2,5
    1,4,3,5,2
    1,4,5,2,3
    1,4,5,3,2
    1,5,2,3,4
    1,5,2,4,3
    1,5,3,2,4
    1,5,3,4,2
    1,5,4,2,3
    1,5,4,3,2
    2,1,3,4,5
    2,1,3,5,4
    2,1,4,3,5
    2,1,4,5,3
    2,1,5,3,4
    2,1,5,4,3
    2,3,1,4,5
    2,3,1,5,4
    2,3,4,1,5
    2,3,4,5,1
    2,3,5,1,4
    2,3,5,4,1
    2,4,1,3,5
    2,4,1,5,3
    2,4,3,1,5
    2,4,3,5,1
    2,4,5,1,3
    2,4,5,3,1
    2,5,1,3,4
    2,5,1,4,3
    2,5,3,1,4
    2,5,3,4,1
    2,5,4,1,3
    2,5,4,3,1
    3,1,2,4,5
    3,1,2,5,4
    3,1,4,2,5
    3,1,4,5,2
    3,1,5,2,4
    3,1,5,4,2
    3,2,1,4,5
    3,2,1,5,4
    3,2,4,1,5
    3,2,4,5,1
    3,2,5,1,4
    3,2,5,4,1
    3,4,1,2,5
    3,4,1,5,2
    3,4,2,1,5
    3,4,2,5,1
    3,4,5,1,2
    3,4,5,2,1
    3,5,1,2,4
    3,5,1,4,2
    3,5,2,1,4
    3,5,2,4,1
    3,5,4,1,2
    3,5,4,2,1
    4,1,2,3,5
    4,1,2,5,3
    4,1,3,2,5
    4,1,3,5,2
    4,1,5,2,3
    4,1,5,3,2
    4,2,1,3,5
    4,2,1,5,3
    4,2,3,1,5
    4,2,3,5,1
    4,2,5,1,3
    4,2,5,3,1
    4,3,1,2,5
    4,3,1,5,2
    4,3,2,1,5
    4,3,2,5,1
    4,3,5,1,2
    4,3,5,2,1
    4,5,1,2,3
    4,5,1,3,2
    4,5,2,1,3
    4,5,2,3,1
    4,5,3,1,2
    4,5,3,2,1
    5,1,2,3,4
    5,1,2,4,3
    5,1,3,2,4
    5,1,3,4,2
    5,1,4,2,3
    5,1,4,3,2
    5,2,1,3,4
    5,2,1,4,3
    5,2,3,1,4
    5,2,3,4,1
    5,2,4,1,3
    5,2,4,3,1
    5,3,1,2,4
    5,3,1,4,2
    5,3,2,1,4
    5,3,2,4,1
    5,3,4,1,2
    5,3,4,2,1
    5,4,1,2,3
    5,4,1,3,2
    5,4,2,1,3
    5,4,2,3,1
    5,4,3,1,2
    5,4,3,2,1
    7 answers · 3 days ago
  • I need help with this algebra word problem?

    The larger of two numbers exceeds twice the smaller number by 9. The sum of twice the larger and 5 times the smaller number is 74. If a is the smaller number, which equation determines the correct value of a? I thought it was 5(2a − 9) + 2a = 74, since I assumed that "the smaller number" means to... show more
    The larger of two numbers exceeds twice the smaller number by 9. The sum of twice the larger and 5 times the smaller number is 74. If a is the smaller number, which equation determines the correct value of a? I thought it was 5(2a − 9) + 2a = 74, since I assumed that "the smaller number" means to subtract nine, but the correct answer was 2(2a + 9) + 5a = 74. I don't get it. I thought "the smaller number" means to subtract, not add???? Help??? The first person to give an understandable explanation will have the best answer.
    5 answers · 3 hours ago
  • Find two numbers such that the sum of the first and 3 times the second is 33, while 8 times the second exceeds 3 times the first by 20.?

    Best answer: a + 3b = 33
    8b = 3a + 20

    a = 33 - 3b

    8b = 3 * (33 - 3b) + 20
    8b = 99 - 9b + 20
    8b + 9b = 99 + 20
    17b = 119
    b = 119/17
    b = 7

    a + 3 * 7 = 33
    a + 21 = 33
    a = 12

    8 * 7 = 56
    3 * 12 + 20 = 56
    Best answer: a + 3b = 33
    8b = 3a + 20

    a = 33 - 3b

    8b = 3 * (33 - 3b) + 20
    8b = 99 - 9b + 20
    8b + 9b = 99 + 20
    17b = 119
    b = 119/17
    b = 7

    a + 3 * 7 = 33
    a + 21 = 33
    a = 12

    8 * 7 = 56
    3 * 12 + 20 = 56
    4 answers · 4 hours ago
  • One math question help please!?

    Describe the transformation(s) that take place on the parent function, f(x) = log(x), to achieve the graph of g(x) = log(-2x-4) + 5. I'm confused about how to do this one, thanks!
    Describe the transformation(s) that take place on the parent function, f(x) = log(x), to achieve the graph of g(x) = log(-2x-4) + 5. I'm confused about how to do this one, thanks!
    4 answers · 8 hours ago
  • I don t understand how to answer this optimization problem.?

    Find two positive numbers that satisfy the given requirements. The sum is S and the product is a maximum. Thanks for the help :)
    Find two positive numbers that satisfy the given requirements. The sum is S and the product is a maximum. Thanks for the help :)
    4 answers · 8 hours ago