Best answer: 1) Let Z be the set of integers and D the set of odd positive integers. Find DΩZ D∩Z = D 2) Let Q = {-2, -1, 0} and R= {-1, 0, 1, 2, 3, 4} QUR QUR = {-2, -1, 0, 1, 2, 3, 4}
Best answer: 1) Let Z be the set of integers and D the set of odd positive integers. Find DΩZ D∩Z = D 2) Let Q = {-2, -1, 0} and R= {-1, 0, 1, 2, 3, 4} QUR QUR = {-2, -1, 0, 1, 2, 3, 4}
1 answer · Mathematics · 9 years ago
• Can someone tell me how to do these math problems?

Best answer: (√12 – √2)/(√3 + √2) = (√12 – √2)(√3 – √2)/(√3 + √2)(√3 – √2) ................................... = (√36 – √24 – √6 + 2)/(3 – 2) ................................... = (6 – 2√6 – √6 + 2)/(1) ................................... = 8 – 3√6 ∛3xy³ – 14∛24xy³ + y∛648x = y∛3x – 14(2y∛3x) +... show more
Best answer: (√12 – √2)/(√3 + √2) = (√12 – √2)(√3 – √2)/(√3 + √2)(√3 – √2) ................................... = (√36 – √24 – √6 + 2)/(3 – 2) ................................... = (6 – 2√6 – √6 + 2)/(1) ................................... = 8 – 3√6 ∛3xy³ – 14∛24xy³ + y∛648x = y∛3x – 14(2y∛3x) + 6y∛3x ........................................... = y∛3x – 28y∛3x + 6y∛3x ........................................... = –21y∛3x
1 answer · Mathematics · 9 years ago

Best answer: N = 3 × 15 × 4 = 180
Best answer: N = 3 × 15 × 4 = 180
3 answers · Mathematics · 9 years ago
• How do you solve 5 then 252p3 under the radical sign?

Best answer: 5√[252p³] = 5√[(36p²)(7p)] .............. = 5√(36p²)√(7p) .............. = 5(6p)√(7p) .............. = 30p√7p
Best answer: 5√[252p³] = 5√[(36p²)(7p)] .............. = 5√(36p²)√(7p) .............. = 5(6p)√(7p) .............. = 30p√7p
3 answers · Mathematics · 9 years ago
• A rectangle has a perimeter of 84 inches and a width of 18 inches. What is the length of the rectangle?

Best answer: A rectangle has a perimeter of 84 inches and a width of 18 inches. What is the length of the rectangle? P = 2W + 2L 84 = 2(18) + 2L 84 = 36 + 2L 48 = 2L L = 48/2 = 24 inches a. 22 b. 24.................... correct answer c. 48 d. 66
Best answer: A rectangle has a perimeter of 84 inches and a width of 18 inches. What is the length of the rectangle? P = 2W + 2L 84 = 2(18) + 2L 84 = 36 + 2L 48 = 2L L = 48/2 = 24 inches a. 22 b. 24.................... correct answer c. 48 d. 66
2 answers · Mathematics · 9 years ago
• Find all real zeros of the function?

Best answer: f(x) = 4x⁴ – 4x³ + 13x² + 18x + 5 Possible rational zeroes x = ±5, ±1, ±5/4, ±5/2, ±1/4, ±1/2 Trying all these values, we find f(–1/2) = 4(–1/2)⁴ – 4(–1/2)³ + 13(–1/2)² + 18(–1/2) + 5 = 0 (2x + 1) is a factor By long division .............2x³ – 3x² + 8x + 5 ...........______________________ 2x + 1 ) 4x⁴ – 4x³ + 13x² + 18x... show more
Best answer: f(x) = 4x⁴ – 4x³ + 13x² + 18x + 5 Possible rational zeroes x = ±5, ±1, ±5/4, ±5/2, ±1/4, ±1/2 Trying all these values, we find f(–1/2) = 4(–1/2)⁴ – 4(–1/2)³ + 13(–1/2)² + 18(–1/2) + 5 = 0 (2x + 1) is a factor By long division .............2x³ – 3x² + 8x + 5 ...........______________________ 2x + 1 ) 4x⁴ – 4x³ + 13x² + 18x + 5 ..............4x⁴ + 2x³ .............---------------------------... ....................– 6x³ + 13x² + 18x + 5 ....................– 6x³ – 3x² ...................---------------------... ...................................16x² + 18x + 5 ...................................16x² + 8x ...................................-----... ........................................... + 5 ........................................... + 5 ........................................... f(x) = 2x³ – 3x² + 8x + 5 Possible rational zeroes x = ±5, ±1, ±5/2, ±1/2 Trying all these values, we find f(–1/2) = 2(–1/2)³ – 3(–1/2)² + 8(–1/2) + 5 = 0 (2x + 1) is again a factor By long division again: ..............x² – 2x + 5 ..........._________________ 2x + 1 ) 2x³ – 3x³ + 8x + 5 ..............2x³ + 1x³ .............------------------------- ....................– 4x³ + 8x + 5 ....................– 4x³ – 2x ...................---------------------... ...............................10x + 5 ...............................10x + 5 ..............................----------... Therefore f(x) = (2x + 1)(2x + 1)(x² – 2x + 5) (x² – 2x + 5) = 0 x = {–(–2) ± √[(–2)² – 4(1)(5)]/2(1) x = (2 ± √–16)/2 x = (2 ± 4i)/2 x = 1 ± 2i The four zeroes are {–1/2, –1/2, 1 – 2i, 1 + 2i} f(x) = 4x² = x³ x³ – 4x² = 0 x²(x – 4) = 0 x² = 0 x = 0 (multiplicity 2) (x – 4) = 0 x = 4 zeroes are x = {0, 0, 4}
1 answer · Mathematics · 9 years ago
• Find the area of the triangle with vertices A(0,0); B(3,2) and C(-2,7)?

Best answer: A = ½|(x₁y₂ + x₂y₃ + x₃y₁ – x₂y₁ – x₃y₂ – x₁y₃)| A = ½|((0)(2) + (3)(7) + (–2)(0) – (3)(0) – (–2)(2) – (0)(7))| A = ½|(0 + 21 + 0 – 0 + 4 – 0)| A = ½|(25)| A = 12 ½
Best answer: A = ½|(x₁y₂ + x₂y₃ + x₃y₁ – x₂y₁ – x₃y₂ – x₁y₃)| A = ½|((0)(2) + (3)(7) + (–2)(0) – (3)(0) – (–2)(2) – (0)(7))| A = ½|(0 + 21 + 0 – 0 + 4 – 0)| A = ½|(25)| A = 12 ½
1 answer · Mathematics · 9 years ago
• Can you help me on percent errors?

Best answer: h : 1.5 : : 3 : .015 h = 1.5(3)/.015 = 300 m
Best answer: h : 1.5 : : 3 : .015 h = 1.5(3)/.015 = 300 m
1 answer · Mathematics · 9 years ago
• HELP ME DO THIS!!! 10 points!!?...?

Best answer: You have already done it! What do you want us to do?
Best answer: You have already done it! What do you want us to do?
1 answer · Mathematics · 9 years ago
• Complicated Circle Question? Help will be appreciated. Thanks. :)?

Best answer: Let r₁, r₂ be the radii of e two concentric circles Let d be the length of the length of line from center of circle(s) to midpoint of chord. In smaller circle: r₁² – 6² = d² In larger circle: r₂² – 18² = d² r₁² – 6² = r₂² – 18² r₁² – 36 = r₂² – 324 r₁² = r₂² – 288 r₁ + r₂ = 40 r₂ = 40 – r₁ r₁² = (40 – r₁)² – 288 r₁² =... show more
Best answer: Let r₁, r₂ be the radii of e two concentric circles Let d be the length of the length of line from center of circle(s) to midpoint of chord. In smaller circle: r₁² – 6² = d² In larger circle: r₂² – 18² = d² r₁² – 6² = r₂² – 18² r₁² – 36 = r₂² – 324 r₁² = r₂² – 288 r₁ + r₂ = 40 r₂ = 40 – r₁ r₁² = (40 – r₁)² – 288 r₁² = 1600 – 80r₁ + r₁² – 288 80r₁ = 1600 – 288 = 1312 r₁ = 1312/80 = 16.4 A = kπ = π(16.4²) k = 16.4² = 268.96
1 answer · Mathematics · 9 years ago
• Are these two math question correct?

Best answer: You got the intermediate steps correct. It is when you go to the final answer that you made an error. You should retain the inequality symbol when you give the final answer. The final answers are: 1. x > 1 2. x ≤ 2.4
Best answer: You got the intermediate steps correct. It is when you go to the final answer that you made an error. You should retain the inequality symbol when you give the final answer. The final answers are: 1. x > 1 2. x ≤ 2.4
9 answers · Mathematics · 9 years ago
• Try to prove the answer to this pre-cal problem?

Best answer: B = sinˉ¹(7.000 sin 115º / 14.5) = 25.946257º C = 180º – (115º + 25.946257º) = 39.053743º c = 14.5 sin 39.053743º/ sin 115º = 10.08014
Best answer: B = sinˉ¹(7.000 sin 115º / 14.5) = 25.946257º C = 180º – (115º + 25.946257º) = 39.053743º c = 14.5 sin 39.053743º/ sin 115º = 10.08014
1 answer · Mathematics · 9 years ago
• Which is the solution set for x2 - 5x - 14 = 0?

Best answer: x² – 5x – 14 = 0 (x + 2)(x – 7) = 0 (x + 2) = 0 x = –2 (x – 7) = 0 x = 7 x = {–2, 7}
Best answer: x² – 5x – 14 = 0 (x + 2)(x – 7) = 0 (x + 2) = 0 x = –2 (x – 7) = 0 x = 7 x = {–2, 7}
2 answers · Mathematics · 9 years ago
• About how long is each diagonal sidewalk?

Best answer: diagonal = √[300² + 300²] = 300√2 = 424 ft
Best answer: diagonal = √[300² + 300²] = 300√2 = 424 ft
1 answer · Mathematics · 9 years ago
• Help with math question?

Best answer: y = ⅓x – 5 For x = 6 y = (1/3)(6) – 5 = 2 – 5 = –3 So you plot the point (6, –3) Then go right 3 units and up one unit. Continue and connect the points and you will have your line.
Best answer: y = ⅓x – 5 For x = 6 y = (1/3)(6) – 5 = 2 – 5 = –3 So you plot the point (6, –3) Then go right 3 units and up one unit. Continue and connect the points and you will have your line.
1 answer · Mathematics · 9 years ago
• Newton's Method Question!?

Best answer: f(x) = x² + x – 1 f'(x) = 2x + 1 x0 = 1 f(x0) = f(1) = (1)² + (1) – 1 = 1 f'(x0) = f'(1) = 2(1) + 1 = 3 x₁ = x0 – f(x0)/f'(x0) = 1 – (1)/(3) = 2/3 f(x₁) = f(2/3) = (2/3)² + (2/3) – 1 = 1/9 f'(x₁) = f'(2/3) = 2(2/3) + 1 = 7/3 x₂ = x₁ – f(x₁)/f'(x₁) = 2/3 - (1/9)/(7/3) = 13/21 f(x₂) = f(13/21) =... show more
Best answer: f(x) = x² + x – 1 f'(x) = 2x + 1 x0 = 1 f(x0) = f(1) = (1)² + (1) – 1 = 1 f'(x0) = f'(1) = 2(1) + 1 = 3 x₁ = x0 – f(x0)/f'(x0) = 1 – (1)/(3) = 2/3 f(x₁) = f(2/3) = (2/3)² + (2/3) – 1 = 1/9 f'(x₁) = f'(2/3) = 2(2/3) + 1 = 7/3 x₂ = x₁ – f(x₁)/f'(x₁) = 2/3 - (1/9)/(7/3) = 13/21 f(x₂) = f(13/21) = (13/21)² + (13/21) – 1 = 1/441 f'(x₂) = f'(13/21) = 2(13/21) + 1 = 47/21 x₃ = x₂ – f(x₂)/f'(x₂) = 13/21 - (1/441)/(47/21) = 610/987 = 0.618 f(x₃) = f(0.618) = (0.618)² + (0.618) – 1 = –0.000076 f'(x₃) = f'(0.618) = 2(0.618) + 1 = 2.236 x₄ = x₃ – f(x₃)/f'(x₃) = 0.618 – (–0.000076)/(2.236) = 0.618034 f(x₄) = f(0.618034) = (0.618034)² + (0.618034) – 1 = 0.000000025156 f'(x₄) = f'(0.618034) = 2(0.618034) + 1 = 2.236 x₅ = x₄ – f(x₄)/f'(x₄) = 0.618034 – (0.000000025156)/(2.236) = 0.6180339887 x = 0.6180339887 That is accurate enough
1 answer · Mathematics · 9 years ago

Best answer: log_b 26 + log_b 2 = log_b (26)(2) = log_b 52
Best answer: log_b 26 + log_b 2 = log_b (26)(2) = log_b 52
2 answers · Mathematics · 9 years ago

Best answer: cos (2π/3) = cos (π – π/3) = –cos (π/3) = –1/2
Best answer: cos (2π/3) = cos (π – π/3) = –cos (π/3) = –1/2
1 answer · Mathematics · 9 years ago
• Write the decimal in the form indicated.?

Best answer: No! The correct expanded exponential form is: 2 ∙ 10² + 6 ∙ 10¹ + 1 ∙ 10⁰ + 0 ∙ 10ˉ¹ + 9 ∙ 10ˉ² You got the positive exponents off by 1
Best answer: No! The correct expanded exponential form is: 2 ∙ 10² + 6 ∙ 10¹ + 1 ∙ 10⁰ + 0 ∙ 10ˉ¹ + 9 ∙ 10ˉ² You got the positive exponents off by 1
2 answers · Mathematics · 9 years ago