• If you roll three fair dice, what is the probability that you roll a total of 13? Express your answer as a fraction.?

    Best answer: You need to find out how many of the 216 (6³) possible outcomes are 13. low roll is 3, high roll is 18: 3 - 1 way (1-1-1) 4 - 3 ways (1-1-2, 1-2-1, 2-1-1) 5 - 6 ways (1-1-3, 1-3-1, 3-1-1, 1-2-2, 2-1-2, 2-2-1) without listing them all, the rest works out to be: 6 - 10 ways 7 - 15 ways 8 - 21 ways 9 - 25 ways 10 - 27 ways 11 - 27... show more
    Best answer: You need to find out how many of the 216 (6³) possible outcomes are 13. low roll is 3, high roll is 18: 3 - 1 way (1-1-1) 4 - 3 ways (1-1-2, 1-2-1, 2-1-1) 5 - 6 ways (1-1-3, 1-3-1, 3-1-1, 1-2-2, 2-1-2, 2-2-1) without listing them all, the rest works out to be: 6 - 10 ways 7 - 15 ways 8 - 21 ways 9 - 25 ways 10 - 27 ways 11 - 27 ways 12 - 25 ways 13 - 21 ways 14 - 15 ways 15 - 10 ways 16 - 6 ways 17 - 3 ways 18 - 1 way So now that we have that, there are 21 ways to get a 13, so we have: 21/216 which reduces to: 7/72
    1 answer · Mathematics · 3 years ago
  • Is the Nintendo 2DS a good option for a teen with not alot of gaming experience or money?

    Best answer: Teens mostly are all anti-Nintendo since they say it's all "Kiddy" and stuff. It's not true anymore. They are getting M-rated games on the Switch and getting good reviews. Anyway, what you like is none of anyone else's business. You like what you like. If you think you like Nintendo games, then get Nintendo... show more
    Best answer: Teens mostly are all anti-Nintendo since they say it's all "Kiddy" and stuff. It's not true anymore. They are getting M-rated games on the Switch and getting good reviews. Anyway, what you like is none of anyone else's business. You like what you like. If you think you like Nintendo games, then get Nintendo hardware. Note that the 3DS family of systems (of which the 2DS is part of) is likely on its last year. 3DS started in 2011 so is already 7 years old and they still have games planned to come out into 2019. But I don't see games coming out much later than that. So if you do get a 2DS or 3DS, know to look back at the existing catalog (including DS games as they are backward compatible) for content. If you only look at what is coming, you're not going to find much. If you are interested in what's coming, look into Nintendo Switch. It's about twice the price of a New 2DS XL, but already has some great games out for it (Zelda, Mario, etc). It's just starting its second year so should have many years of new comes coming. I grew up on Nintendo games, played NES games in high school, SNES games in college, and still play games as I raise the next generation of gamers.
    2 answers · Video & Online Games · 1 day ago
  • Stuck on a stats problem for my hw?

    Best answer: There are 10,000 possible numbers that can be created in a pick-4. The probability that you win is then 1/10000 Thus the probability that you lose (presuming there are no other sub-prizes, which there usually are, but none mentioned in your story) is 9999/10000 It costs 50 cents to buy a ticket. So in the probable event that you... show more
    Best answer: There are 10,000 possible numbers that can be created in a pick-4. The probability that you win is then 1/10000 Thus the probability that you lose (presuming there are no other sub-prizes, which there usually are, but none mentioned in your story) is 9999/10000 It costs 50 cents to buy a ticket. So in the probable event that you lose, you end up losing 50 cents. If you win, you win $2,500, but you still had to pay the 50 cents, so the profit is $2,499.50 To find the expected outcome, you multiply the result by the probability, then add the results together: winning: 2499.50 * 1/10000 = 2499.5 / 10000 = 0.24995 losing (remember you lose money, so the amount is negative): -0.5 * 9999/10000 = -4999.5 / 10000 = -0.49995 Now add those results: 0.24995 - 0.49995 = -0.25 The expected result is you lose 25 cents per play.
    6 answers · Mathematics · 1 day ago
  • Hey guys just a quest when i order from amazon multiple items will they all arrive at the same time?

    Best answer: If many items come from the same warehouse, multiple orders may even be packaged into a single box.
    Best answer: If many items come from the same warehouse, multiple orders may even be packaged into a single box.
    2 answers · Video & Online Games · 3 days ago
  • Playing Rockband on the old wii, you could go to the store and buy songs, but now the store is no more, so...can you still find these songs?

    Best answer: You can no longer add Wii Points to your account. They ended that at the end of last month. If you do still have points on it, you should be able to buy content (until January of next year).
    Best answer: You can no longer add Wii Points to your account. They ended that at the end of last month. If you do still have points on it, you should be able to buy content (until January of next year).
    2 answers · Nintendo Wii · 6 days ago
  • How do game reviewers manage to play so many games and invest so many hours into them?

    Best answer: They get the games early (usually 1-2 weeks, sometimes more for larger games). And that's usually their full-time job, so they play games all day and write reviews. I'm part of a podcast group that does do small reviews from time to time and we usually only get games a few days to a week early. Since this isn't our... show more
    Best answer: They get the games early (usually 1-2 weeks, sometimes more for larger games). And that's usually their full-time job, so they play games all day and write reviews. I'm part of a podcast group that does do small reviews from time to time and we usually only get games a few days to a week early. Since this isn't our full-time job, we can't do a lot of reviews and don't go into full 3,000 word essays about it, instead we may have a 2-3 min video or talk about it on the podcast for a few minutes talking about our thoughts and if we like what we've played and if we would recommend it.
    5 answers · Video & Online Games · 3 days ago
  • Math question, please help?

    Best answer: Two ways you can tackle this. 1) Solve the equation setting y = 0, which is pretty simple since it's already in vertex form, or 2) Put into standard form, then check the discriminant. If negative, 0 real solutions. If 0, one real solution. If positive, two real solutions. You will never have three real solutions to a quadratic,... show more
    Best answer: Two ways you can tackle this. 1) Solve the equation setting y = 0, which is pretty simple since it's already in vertex form, or 2) Put into standard form, then check the discriminant. If negative, 0 real solutions. If 0, one real solution. If positive, two real solutions. You will never have three real solutions to a quadratic, so we can take that off the table now. I'll show you with the discriminant first, then show you by solving it: 0 = -(x + 1)² - 2 expand this and put it into standard form: 0 = -(x² + 2x + 1) - 2 0 = -x² - 2x - 1 - 2 0 = -x² - 2x - 3 Now find the discriminant using a = -1, b = -2, and c = -3: b² - 4ac (-2)² - 4(-1)(-3) 4 - 12 -8 It is negative so there are zero real roots (both are complex roots) So if we try to solve this we should get the same result. Starting from here: 0 = -(x + 1)² - 2 Add 2 to both sides, multiply both sides by -1, then square root both sides: 2 = -(x + 1)² -2 = (x + 1)² Here is where we see there are no real roots. Getting the square root of a negative number results in complex solutions. So we can stop here and say that there are no real roots.
    7 answers · Mathematics · 3 days ago
  • My Nintendo switch joy cons detach and then don t work when detached.?

    Best answer: Call Nintendo support for a replacement. The battery pack may have failed so it can't hold or release a charge, but still works when attached as it won't need the battery at that point.
    Best answer: Call Nintendo support for a replacement. The battery pack may have failed so it can't hold or release a charge, but still works when attached as it won't need the battery at that point.
    1 answer · Video & Online Games · 8 months ago
  • What is the length of segment AD?

    Best answer: The angle bisector theorem states that the ratio of the length of the line segment CD to the length of segment AD is equal to the ratio of the length of side BC to the length of side AB: So that gives us: 12 / x = 15 / 7 Solving for x: 15x = 84 x = 5.6 cm (answer C)
    Best answer: The angle bisector theorem states that the ratio of the length of the line segment CD to the length of segment AD is equal to the ratio of the length of side BC to the length of side AB: So that gives us: 12 / x = 15 / 7 Solving for x: 15x = 84 x = 5.6 cm (answer C)
    4 answers · Mathematics · 1 week ago
  • Should people be allowed to experience forbidden sex in virtual reality as it gets more and more realistic?

    Best answer: Then it would no longer be forbidden, thus making your question null and void.
    Best answer: Then it would no longer be forbidden, thus making your question null and void.
    1 answer · Video & Online Games · 2 weeks ago
  • Expotential and logarithmic functions?

    Best answer: So you are given the equation: A = A₀(1.05)^t where A₀ = 5000, so: A = 5000(1.05)^t Solve for A when the year is 1998. So solve for t (number of years between 1938 - 1998), then solve for A: t = 1998 - 1938 t = 60 so: A = 5000(1.05)^60 Now simplify: A = 5000(18.67919) (rounded here, but not in my calculator) A = $93,395.93... show more
    Best answer: So you are given the equation: A = A₀(1.05)^t where A₀ = 5000, so: A = 5000(1.05)^t Solve for A when the year is 1998. So solve for t (number of years between 1938 - 1998), then solve for A: t = 1998 - 1938 t = 60 so: A = 5000(1.05)^60 Now simplify: A = 5000(18.67919) (rounded here, but not in my calculator) A = $93,395.93 (rounded to nearest penny) ---- Jumping to part C, if A₀= 10000, what's A? Same equation and value for "t", just a new A₀: A = A₀(1.05)^t A = 10000(1.05)^60 A = 10000(18.67919) (rounded here, but not in my calculator) A = $186,791.86 (rounded to nearest penny ---- For the middle one, what year when $25,000 is in the account. Use that for A and solve for t: 25000 = 5000(1.05)^t Divide both sides by 5000: 5 = 1.05^t log of both sides: ln(5) = ln(1.05^t) You can pull the exponent out of the log: ln(5) = t ln(1.05) Divide both sides by t's coefficient: t = ln(5) / ln(1.05) Getting an estimate for t using a calculator: t ≈ 32.99 Round that up to 33 years, then add the initial year of 1938 to get the year: 1971
    2 answers · Mathematics · 3 weeks ago
  • Twice the sum of a number and seven is three times the number.?

    Best answer: You started it right. 2x + 14 = 3x Now move the "x" terms together, so I'll subtract 2x from both sides: 14 = x So your number is 14. Testing it, twice the sum of 14 and 7 is: 2(14 + 7) 2(21) 42 is three times the number: 14 * 3 = 42 They are the same, so this is the correct answer.
    Best answer: You started it right. 2x + 14 = 3x Now move the "x" terms together, so I'll subtract 2x from both sides: 14 = x So your number is 14. Testing it, twice the sum of 14 and 7 is: 2(14 + 7) 2(21) 42 is three times the number: 14 * 3 = 42 They are the same, so this is the correct answer.
    5 answers · Mathematics · 2 weeks ago
  • Math problem: I have to solve it by creating two linear equations and then solve it using substitution?

    Best answer: Let x = number of 1/4 lb. burgers sold Let y = number of 1/2 lb. burgers sold One month they sold 3 times as many 1/2 lb. burgers as 1/4 lb. burgers: y = 3x If the total mixture was 378 lbs. what was the total number of burgers sold that month (so you are asked for "x + y"). Since x is 1/4 lb. burgers, the amount of mixture... show more
    Best answer: Let x = number of 1/4 lb. burgers sold Let y = number of 1/2 lb. burgers sold One month they sold 3 times as many 1/2 lb. burgers as 1/4 lb. burgers: y = 3x If the total mixture was 378 lbs. what was the total number of burgers sold that month (so you are asked for "x + y"). Since x is 1/4 lb. burgers, the amount of mixture used to make the burger is: x/4 lb. And the same with y with the 1/2 lb. burgers: y/2 lb. so adding them together gives us the total weight of 378 lbs: x/4 + y/2 = 378 To simplify this, let's multiply both sides by 4 to get rid of the fractions: x + 2y = 1512 Now we have two equations and two unknowns. To solve by substitution we can substitute "y" for its expression in terms of x from the first equation into the second one, then solve for x: x + 2(3x) = 1512 x + 6x = 1512 7x = 1512 x = 216 Now we can solve for y: y = 3x y = 3(216) y = 648 So the total number of burgers sold was: x + y 216 + 648 864 burgers
    2 answers · Mathematics · 2 weeks ago
  • Why is it so wrong for an adult man to like the Nintendo Switch instead of PlayStation or Xbox?

    Best answer: You just have to learn to ignore the haters. There is a community of Nintendo-gaming adults. I co-host the Nintendo Dads Podcast where we give Nintendo news, reviews, and opinions from a parenting perspective (which then also includes the adult perspective when talking about games that are not children friendly). So our audience skews... show more
    Best answer: You just have to learn to ignore the haters. There is a community of Nintendo-gaming adults. I co-host the Nintendo Dads Podcast where we give Nintendo news, reviews, and opinions from a parenting perspective (which then also includes the adult perspective when talking about games that are not children friendly). So our audience skews a bit older than the traditional Nintendo podcast. If you like what you play, go nuts. Ignore the haters and do you.
    2 answers · Video & Online Games · 2 weeks ago
  • How do you prove log_b (a) * log_a (b) = 1?

    Best answer: The base-change for logs is: log_x(y) = log_k(y) / log_k(x) Where k is any other base, as long as they are the same on both sides of the fraction. So I'll use base "e" and use natrual logs. so you have: log_b(a) * log_a(b) = 1 changing the bases we get: [ln(a) / ln(b)] [ln(b) / ln(a)] = 1 Now we have the product of... show more
    Best answer: The base-change for logs is: log_x(y) = log_k(y) / log_k(x) Where k is any other base, as long as they are the same on both sides of the fraction. So I'll use base "e" and use natrual logs. so you have: log_b(a) * log_a(b) = 1 changing the bases we get: [ln(a) / ln(b)] [ln(b) / ln(a)] = 1 Now we have the product of two "factored" fractions. the ln(b)'s cancel and the ln(a)'s cancel as there are one of each in a numerator and a denominator. This cancels everything out except for the 1's: 1 / 1 = 1 1 = 1 TRUE So we just showed that log_b(a) * log_a(b) = 1 no matter what "a" and "b" are.
    1 answer · Mathematics · 2 weeks ago
  • Need some help with this math question?

    Best answer: The general form for the "n"th term of an arithmetic sequence is: a(n) = a + b(n - 1) Where a is the first term and b is the common difference between terms. If your case, a = 12 and b = -6. Substitute and simplify to get: a(n) = 12 - 6(n - 1) a(n) = 12 - 6n + 6 a(n) = 18 - 6n Answer A.
    Best answer: The general form for the "n"th term of an arithmetic sequence is: a(n) = a + b(n - 1) Where a is the first term and b is the common difference between terms. If your case, a = 12 and b = -6. Substitute and simplify to get: a(n) = 12 - 6(n - 1) a(n) = 12 - 6n + 6 a(n) = 18 - 6n Answer A.
    6 answers · Mathematics · 2 weeks ago
  • I purchased a soft modded Wii and I would like to remove the SD card to delete some unwanted apps and games and add things but...?

    Best answer: As long as you don't delete content that it needs to do what it does, yes. I've removed, deleted/added content, and re-insert my SD card from my Wii dozens of times as I upgraded apps, etc.
    Best answer: As long as you don't delete content that it needs to do what it does, yes. I've removed, deleted/added content, and re-insert my SD card from my Wii dozens of times as I upgraded apps, etc.
    1 answer · Nintendo Wii · 2 weeks ago
  • You can use square roots to solve a quadratic when the problem is in the form: A) or B)?

    Best answer: You didn't give us what the options are, but the answer is: (x + b)² = c (or some variables). If we get the square root of both sides, then subtract b from both sides, we end up with: x = -b ± √c
    Best answer: You didn't give us what the options are, but the answer is: (x + b)² = c (or some variables). If we get the square root of both sides, then subtract b from both sides, we end up with: x = -b ± √c
    1 answer · Mathematics · 2 months ago
  • I need help?

    Best answer: The height of the tree grows more slowly every year. The first year it grew 1.5 m The second year it then grew 1.5 (14/15) (or 1.4 m) So this turns into a geometric sequence showing the amount of growth per year, where the "n"th term is: a(n) = a(14/15)^(n - 1) Where a is the growth of the first year (1.5) and "n"... show more
    Best answer: The height of the tree grows more slowly every year. The first year it grew 1.5 m The second year it then grew 1.5 (14/15) (or 1.4 m) So this turns into a geometric sequence showing the amount of growth per year, where the "n"th term is: a(n) = a(14/15)^(n - 1) Where a is the growth of the first year (1.5) and "n" is the number of years, so this turns into: a(n) = 1.5(14/15)^(n - 1) The sum of a geometric sequence to infinity when the common ratio is -1 < x < 1 is: S = a / (1 - b) Where a is the first term and b is the common ratio. Using a = 1.5 and b = 14/15, we get: S = 1.5 / (1 - 14/15) S = 1.5 / (1/15) S = 1.5 * 15 S = 22.5 m is the maximum growth. Though this doesn't get close to this value until is closer to 90 years. So instead we need an equation for the first "n" terms of a geometric sequence, which is: S(n) = a(1 - b^n) / (1 - b) So now using a = 1.5, b = 14/15, and n = 20, we get: S(20) = 1.5(1 - (14/15)^20) / (1 - 14/15) S(20) = 1.5(1 - (0.933333)^20) / (1 - 14/15) (I'm rounding here for readability, but not rounding in my calculator to reduce rounding errors) S(20) = 1.5(1 - 0.25161) / (1/15) S(20) = 1.5(0.74839) / (1/15) S(20) = 1.12258 / (1/15) S(20) = 1.12258 * 15 S(20) = 16.8 m (rounded to 1 DP). This is the answer to your question. If this helped, please give best answer. Thanks.
    4 answers · Mathematics · 2 weeks ago
  • A farmer would like to fence off two adjacent and equivalent rectangular areas along a barn. He has 360 feet of fence.?

    Best answer: You can see by the diagram that the fence would create three lengths and one width (with the barn taking the space of the other width in the rectangle). So the amount of fencing material needed would be: 3l + w You are told he has 360 ft of material, so: 360 = 3l + w Let's solve this for w in terms of l: w = 360 - 3l You want... show more
    Best answer: You can see by the diagram that the fence would create three lengths and one width (with the barn taking the space of the other width in the rectangle). So the amount of fencing material needed would be: 3l + w You are told he has 360 ft of material, so: 360 = 3l + w Let's solve this for w in terms of l: w = 360 - 3l You want the maximum area, so let's start with that equation: A = lw Now we can substitute the w with the expression in terms of l from above: A = l(360 - 3l) simplified: A = 360l - 3l² To find the length that gives the maximum area, solve for the zero of the first derivative: dA/dl = 360 - 6l 0 = 360 - 6l 6l = 360 l = 60 Now that we have l, we can solve for w: w = 360 - 3l w = 360 - 3(60) w = 360 - 180 w = 180 The dimensions are: 60 ft by 180ft and gives an area of: 60 * 180 = 10,800 ft²
    2 answers · Mathematics · 2 weeks ago