• Is it true that you can no longer play wii games online?

    Best answer: You've not been able to play most Wii or DS games online since May of 2014 (almost 5 years) Some games that didn't run on WFC (Wi-Fi Connect) may still have servers running, but that would vary from game-to-game.
    Best answer: You've not been able to play most Wii or DS games online since May of 2014 (almost 5 years) Some games that didn't run on WFC (Wi-Fi Connect) may still have servers running, but that would vary from game-to-game.
    2 answers · Nintendo Wii · 1 day ago
  • Grade 11 functions math questions?

    Best answer: The general form for the n-th term of an arithmetic sequence is: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. You are told that: a(4) = 4x + 3y and a(7) = 11/2x - 3y I'm going with it as written, like (11/2)x - 3y, vs. 11 / (2x - 3y). If we substitute what we know into the general form, we can... show more
    Best answer: The general form for the n-th term of an arithmetic sequence is: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. You are told that: a(4) = 4x + 3y and a(7) = 11/2x - 3y I'm going with it as written, like (11/2)x - 3y, vs. 11 / (2x - 3y). If we substitute what we know into the general form, we can solve for a and b in terms of x and y: a(n) = a + b(n - 1) a(4) = a + b(4 - 1) and a(7) = a + b(7 - 1) 4x + 3y = a + 3b and 11/2x - 3y = a + 6b Solve the first for a in terms of b, x, and y, then substitute into the second equation to solve for b: 4x + 3y = a + 3b 4x + 3y - 3b = a 11/2x - 3y = a + 6b 11/2x - 3y = 4x + 3y - 3b + 6b 11/2x - 3y = 4x + 3y + 3b Let's multiply both sides by 2 to get rid of the fraction: 11x - 6y = 8x + 6y + 6b Move the x and y terms to the left side: 3x - 12y = 6b Divide both sides by 6: (1/2)x - 2y = b Now we can solve for a: a = 4x + 3y - 3b a = 4x + 3y - 3[(1/2)x - 2y] a = 4x + 3y - (3/2)x + 6y a = (8/2)x - (3/2)x + 9y a = (5/2)x + 9y So using these expressions for "a" and "b", our general form is now: a(n) = a + b(n - 1) a(n) = (5/2)x + 9y + [(1/2)x - 2y](n - 1) Simplifying: a(n) = (5/2)x + 9y + (1/2)nx - (1/2)x - 2ny + 2y Add the "x" and "y" terms: a(n) = (4/2)x + 11y + (1/2)nx - 2ny a(n) = 2x + 11y + (1/2)nx - 2ny Now that we have that, let's look at the equation for the sum of the first "n" terms: S(n) = [a + a(n)]n / 2 We have an expression for "a" and a(n), so we can substitute those and simplify: S(n) = [(5/2)x + 9y + 2x + 11y + (1/2)nx - 2ny]n / 2 S(n) = [(5/2)x + (4/2)x + 20y + (1/2)nx - 2ny]n / 2 S(n) = [(9/2)x + 20y + (1/2)nx - 2ny]n / 2 S(n) = [(9/2)nx + 20ny + (1/2)n²x - 2n²y] / 2 Turn the division into the multiplication of reciprocal, and multiply: S(n) = [(9/2)nx + 20ny + (1/2)n²x - 2n²y] * (1/2) S(n) = (9/4)nx + 10ny + (1/4)n²x - n²y We are asked for the sum of the 3rd through 10th terms. So if we find the sum of the first 10 terms then subtract out the sum of the first 2 terms, we'll get the 3 through 10 left: S(n) = (9/4)nx + 10ny + (1/4)n²x - n²y S(10) = (9/4)(10)x + 10(10)y + (1/4)(10)²x - 10²y and S(2) = (9/4)(2)x + 10(2)y + (1/4)(2)²x - 2²y S(10) = (90/4)x + 100y + (1/4)(100)x - 100y and S(2) = (18/4)x + 20y + (1/4)(4)x - 4y S(10) = (45/2)x + 100y + 25x - 100y and S(2) = (9/2)x + 20y + x - 4y S(10) = (45/2)x + 25x and S(2) = (9/2)x + 16y + x S(10) = (45/2)x + (50/2)x and S(2) = (9/2)x + 16y + (2/2)x S(10) = (95/2)x and S(2) = (11/2)x + 16y We can subtract them to get: (95/2)x - [(11/2)x + 16y] (95/2)x - (11/2)x - 16y (84/2)x - 16y 42x - 16y That will be the sum of the 3rd through 10th terms of your sequence.
    2 answers · Mathematics · 1 day ago
  • If a number is added to the numerator of 2/5...?

    Best answer: Starting from the previous equation: (2 + n) / (5 - n) = 6 We know that n cannot be 5 otherwise, we are dividing by zero. Multiply both sides of the equation by the denominator: 2 + n = 6(5 - n) Expand the right side: 2 + n = 30 - 6n Move the n's to the left side (add 6n to both sides) and move the constants to the right... show more
    Best answer: Starting from the previous equation: (2 + n) / (5 - n) = 6 We know that n cannot be 5 otherwise, we are dividing by zero. Multiply both sides of the equation by the denominator: 2 + n = 6(5 - n) Expand the right side: 2 + n = 30 - 6n Move the n's to the left side (add 6n to both sides) and move the constants to the right (subtract 2 from both sides) 7n = 28 And finally, divide by 7: n = 4
    4 answers · Mathematics · 2 days ago
  • What is a good “Quadratic Viewing Window” for the quadratic function y=-16x^2+40x+4 ?

    Best answer: Since the maximum is 29, you could have your y-max to be 35 with your y-min being maybe -10 with a y-scale of 5. Roots are at -0.096291 and 2.5963 (approx) so your x-min could be -0.5 and x-max 3.0 with an x-scale of 0.5 Since your scales aren't the same it won't be drawn to scale and depends on your resolution of your... show more
    Best answer: Since the maximum is 29, you could have your y-max to be 35 with your y-min being maybe -10 with a y-scale of 5. Roots are at -0.096291 and 2.5963 (approx) so your x-min could be -0.5 and x-max 3.0 with an x-scale of 0.5 Since your scales aren't the same it won't be drawn to scale and depends on your resolution of your calculator, but at least you will see what's important about the curve (the roots and the vertex).
    1 answer · Mathematics · 3 days ago
  • 275/x-10 = 300/x + 1/2 Find all real solutions to this equation?

    Best answer: ? answered it as-written, but I'm guessing what you really meant was: 275/(x - 10) = 300/x + 1/2 (if this is what you meant, then please learn the importance of proper parenthesis use when it isn't otherwise easy to show what's in a numerator and what's in a denominator. If this is what you want to solve for, then the... show more
    Best answer: ? answered it as-written, but I'm guessing what you really meant was: 275/(x - 10) = 300/x + 1/2 (if this is what you meant, then please learn the importance of proper parenthesis use when it isn't otherwise easy to show what's in a numerator and what's in a denominator. If this is what you want to solve for, then the first thing to note is that x cannot equal 0 or 10 otherwise you are dividing by zero. Now let's multiply everything by the LCD of 2x(x - 10): 550x = 600(x - 10) + x(x - 10) Expand, simplify, and put into standard form. 550x = 600x - 6000 + x² - 10x 550x = 590x - 6000 + x² 0 = 40x - 6000 + x² 0 = x² + 40x - 6000 Let's solve this by completing the square. Starting with adding 6000 to both sides, then we can figure out the next step: 6000 = x² + 40x Half the 40 to 20, then square to 400. Add that to both sides: 6400 = x² + 40x + 400 Factor: 6400 = (x + 20)² Square root: ± 80 = x + 20 Subtract 20 from both sides: x = -20 ± 80 x = -100 and 60 Those are your two solutions for the equation above if my guess as to what you meant is correct.
    4 answers · Mathematics · 3 days ago
  • Another composite question?

    Best answer: Starting from: cos(x + 0.3) = 0.9 If we get the arccos function of both sides, this cancels out the cos function on the left side so we get: x + 0.3 = cos⁻¹(0.9) Using a calculator: x + 0.3 = cos⁻¹(0.9) x + 0.3 = 0.451 Now you can subtract 0.3 from both sides: x = 0.151 (rounded to 3DP) There will be other solutions as well, so... show more
    Best answer: Starting from: cos(x + 0.3) = 0.9 If we get the arccos function of both sides, this cancels out the cos function on the left side so we get: x + 0.3 = cos⁻¹(0.9) Using a calculator: x + 0.3 = cos⁻¹(0.9) x + 0.3 = 0.451 Now you can subtract 0.3 from both sides: x = 0.151 (rounded to 3DP) There will be other solutions as well, so depending on what range of x's you are looking for you may have to include others.
    1 answer · Mathematics · 4 days ago
  • Composite arguments?

    Best answer: If you set: A = 3x B = 37 Then your equation becomes: cos (A + B) = cosA*cosB - sinA * sinB cos (3x + 57) = cos(3x) cos(57) - sin(3x) sin(57) It's just substitution here.
    Best answer: If you set: A = 3x B = 37 Then your equation becomes: cos (A + B) = cosA*cosB - sinA * sinB cos (3x + 57) = cos(3x) cos(57) - sin(3x) sin(57) It's just substitution here.
    1 answer · Mathematics · 4 days ago
  • CAN SOMEONE HELP ME PLEASE?

    Best answer: You do realize that there is a Details box that you can open up to add your details before you post it so you don't have to go back and add it as an update later, right? This is a z-score problem, which requires the use of a z-score table (linked below). It shows the probability of a random point of data being below a given point... show more
    Best answer: You do realize that there is a Details box that you can open up to add your details before you post it so you don't have to go back and add it as an update later, right? This is a z-score problem, which requires the use of a z-score table (linked below). It shows the probability of a random point of data being below a given point indicated by the z-score. The z number is the number of standard deviations away from the mean, so a z-score of 0 is at the mean so 50% of the data is below it. I use this equation to find z-score: n = m + sz Where n is the data point(s) in question (91 and 109) m is the mean (100) s is the standard deviation (15) Solve for the unknowns: n = m + sz 91 = 100 + 15z and 109 = 100 + 15z -9 = 15z and 9 = 15z -9/15 = z and 9/15 = z -0.6 = z and 0.6 = z When you look up a z-score in a table and gives you the probability of a value being below that number. So when you subtract the smaller from the larger if you look at the two graphs, then the overlap gets removed leaving you with the range that you are looking for (between the data points 91 and 109). So now we have: P(z = 0.6) - P(z = -0.6) 0.7257 - 0.2743 Now subtract and that's your answer as a probability. To turn it into a percent, multiply by 100: 0.4514 45.14% The answer is closest to answer B. I'm not sure what rounding your book is expecting you to do, but this is the value that I get based on the table that I use.
    4 answers · Mathematics · 4 days ago
  • How do you write the function 2x^2-12x+11 from standard form to vertex form?

    Best answer: Let's set that to a variable to help us keep our bearings: y = 2x² - 12x + 11 Vertex form is: y = a(x - h)² + k So since we have a binomial squared term in there, we have to have a perfect square trinomial first. So we can complete the square. we need the right side to be in the form of (x² + bx), so we'll start with... show more
    Best answer: Let's set that to a variable to help us keep our bearings: y = 2x² - 12x + 11 Vertex form is: y = a(x - h)² + k So since we have a binomial squared term in there, we have to have a perfect square trinomial first. So we can complete the square. we need the right side to be in the form of (x² + bx), so we'll start with subtracting 11 from both sides, then divide both sides by 2: y - 11 = 2x² - 12x (y - 11)/2 = x² - 6x Now we can complete the square by adding 9 to both sides: (y - 11)/2 + 9 = x² - 6x + 9 Now we can factor the right side: (y - 11)/2 + 9 = (x - 3)² And solve for y again. Starting with subtracting 9 from both sides, then multiply both sides by 2: (y - 11)/2 = (x - 3)² - 9 y - 11 = 2(x - 3)² - 18 Finally, add 11 to both sides: y = 2(x - 3)² - 7 Since what we started with is equal to y and what we ended with is equal to y, both of them are equal to each other: 2x² - 12x + 11 = 2(x - 3)² - 7
    3 answers · Mathematics · 4 days ago
  • Why does -3x^1/3 - 3x^1/3 = -6x^1/3?

    Best answer: You have: -3x^1/3 - 3x^1/3 = -6x^1/3 Presuming you mean: -3x^(1/3) - 3x^(1/3) = -6x^(1/3) Things may be easier to to see if you make this substitution: y = x^(1/3) Then looking at the left half of this we get: -3y - 3y Which of course simplifies to: -6y Then if you substitute the expression in terms of x back in, you... show more
    Best answer: You have: -3x^1/3 - 3x^1/3 = -6x^1/3 Presuming you mean: -3x^(1/3) - 3x^(1/3) = -6x^(1/3) Things may be easier to to see if you make this substitution: y = x^(1/3) Then looking at the left half of this we get: -3y - 3y Which of course simplifies to: -6y Then if you substitute the expression in terms of x back in, you get: -6x^(1/3) The exponents only change if you multiply/divide values of the same base. If you add them, they just work like any other term. If they are different, then they cannot be simplified like this: x^(2/3) + x^(1/3) Cannot be simplified for the same reason that this can't be: y² + y But if you multiplied them together: -3x^(1/3)[-3x^(1/3)] Then the -3's multiply together to get 9 and the x^(1/3)'s multiplied together has you add the exponents to end up with: 9x^(2/3) As you are expecting. Hope this helps in clearing things up.
    5 answers · Mathematics · 5 days ago
  • Format numbers - add dollar sign and commas to price?

    Best answer: double num = 1323.526; NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(); System.out.println("US: " + defaultFormat.format(num));
    Best answer: double num = 1323.526; NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(); System.out.println("US: " + defaultFormat.format(num));
    1 answer · Programming & Design · 5 days ago
  • Three times a number increased by 25?

    Best answer: 3x + 25
    Best answer: 3x + 25
    10 answers · Mathematics · 2 weeks ago
  • What rate of interest has been gained on these two sums of money (pounds sterling) over a 12 month period?

    Best answer: What's being asked here? What's the interest rate? or what's the rate of growth? If the interest rate, we need to know if it's simple, compounded (and how often), or continuous. If it's just the rate of growth, you can divide the amount of change (the interest) by the original amount, then multiply by 100 to get... show more
    Best answer: What's being asked here? What's the interest rate? or what's the rate of growth? If the interest rate, we need to know if it's simple, compounded (and how often), or continuous. If it's just the rate of growth, you can divide the amount of change (the interest) by the original amount, then multiply by 100 to get the percent: 125 / 12000 = 0.0104167 or 1.04167%
    5 answers · Mathematics · 1 week ago
  • How do you write the equation of this line?

    Best answer: You are told that a line goes through the points (-4, 0) and (5, -4) We can find the slope of that line by taking the difference in y's over the difference in x's: m = (0 - (-4)) / (-4 - 5) m = (0 + 4) / (-9) m = -4/9 Then you are told that another line that is parallel goes through the point (-1, -4). Parallel lines have the... show more
    Best answer: You are told that a line goes through the points (-4, 0) and (5, -4) We can find the slope of that line by taking the difference in y's over the difference in x's: m = (0 - (-4)) / (-4 - 5) m = (0 + 4) / (-9) m = -4/9 Then you are told that another line that is parallel goes through the point (-1, -4). Parallel lines have the same slopes, so we know the slope to this line. We know an x and a y, so all we need is the intercept: y = mx + b -4 = (-4/9)(-1) + b -4 = 4/9 + b -4 - 4/9 = b -36/9 - 4/9 = b -40/9 = b So the equation of the line in slope-intercept form is: y = (-4/9)x - 40/9
    3 answers · Mathematics · 2 weeks ago
  • What was your favorite Power Rangers Tv Series Show?!?

    Best answer: I liked Dino Thunder, the return of Tommy. :)
    Best answer: I liked Dino Thunder, the return of Tommy. :)
    6 answers · Video & Online Games · 2 weeks ago
  • How to solve this with either law of cosines or sines?

    Best answer: You are told that angle DAC is 34° and that AD and AC are both 10 cm. Therefore the opposite angles must also be the same. Since the sum of the three angles is always 180°, we can solve for the other two angles, which includes ADC: x + x + 34 = 180 2x = 146 x = 73° That answers part a. For part B, you need angle BAC. Since ADC and... show more
    Best answer: You are told that angle DAC is 34° and that AD and AC are both 10 cm. Therefore the opposite angles must also be the same. Since the sum of the three angles is always 180°, we can solve for the other two angles, which includes ADC: x + x + 34 = 180 2x = 146 x = 73° That answers part a. For part B, you need angle BAC. Since ADC and DCA are the same, and the sum of DCA and BCA is 180 as they are part of a straight line, we can solve for that: 73 + x = 180 x = 107° Again, the sum of the three angles is 180, so now we can look at the right triangle with two known angles and one unknown to solve for the unknown: x + 107 + 42 = 180 x + 149 = 180 x = 31° That's the answer to part b. To find part c, here is where we can use law of sines as all three angles are known and we know the length of AC, so we can use that to find the length of AB: a / sin(A) = b / sin(B) 10 / sin(42) = b / sin(107) 10 sin(107) / sin(42) = b b ≈ 14.292 cm
    1 answer · Mathematics · 2 weeks ago
  • Solve the inequality: [(x-1)³(x+2)²]/(3-x) ≥0.?

    Best answer: [(x - 1)³(x + 2)²] / (3 - x) ≥ 0 Before we start, I want to have all binomials such that the variable is shown first. So if we multiply both sides by -1, we can flip the (3 - x) to (x - 3), and then we have to flip the sign: [(x - 1)³(x + 2)²] / (x - 3) ≤ 0 Now since the (x + 2) term is squared, no matter what "x" is... show more
    Best answer: [(x - 1)³(x + 2)²] / (3 - x) ≥ 0 Before we start, I want to have all binomials such that the variable is shown first. So if we multiply both sides by -1, we can flip the (3 - x) to (x - 3), and then we have to flip the sign: [(x - 1)³(x + 2)²] / (x - 3) ≤ 0 Now since the (x + 2) term is squared, no matter what "x" is it's either zero or positive, so we can ignore that in the next step. We also have to note that x cannot be 3, otherwise, we are dividing by zero. Recall that in both division and multiplication, the product of two negatives is positive and the product of a negative and positive is negative. We'll need that for this step. We have pivots now at x = 1 and x = 3. Using those we can create three ranges and then check for positives and negatives. we want the quotient to be less than zero, or negative: if x > 3 we have positive divided by positive, which is positive, not in our solution set. if 1 < x < 3 we have positive divided by negative, which is negative, in our solution set. if x < 1 we have negative divided by negative, which is positive, not in our solution set. Since the expression is equal to zero is in the solution set, x = 1 is in the set (x = 3 still isn't due to dividing by zero). So your solution so far to this inequality is: 1 ≤ x < 3 We need to now go back to the (x + 2)² term. If x = -2, it's a zero, which when multiplied by anything and divided by anything non-zero is still zero, which is in the solution set. So we have to add that to it. The final answer is: x = -2 and 1 ≤ x < 3
    1 answer · Mathematics · 2 weeks ago
  • What to do when?

    Best answer: Rounding to 1 decimal place puts this value at: 28.0 You have to include the .0
    Best answer: Rounding to 1 decimal place puts this value at: 28.0 You have to include the .0
    5 answers · Mathematics · 2 weeks ago
  • How do I go about drawing and solving this one?

    Best answer: Attached is the sketch that I made which includes the known measurements and two unknowns. You are asked to solve for "y". You have two right triangles with the same "adjacent" length and different angles. We know that tangents can be defined as the ratio of the opposite over the adjacent, so we can create two... show more
    Best answer: Attached is the sketch that I made which includes the known measurements and two unknowns. You are asked to solve for "y". You have two right triangles with the same "adjacent" length and different angles. We know that tangents can be defined as the ratio of the opposite over the adjacent, so we can create two equations with tangents and our two unknowns: First is the smaller one that has the opposite length of "x", the other is the larger one that has the opposite length of "x + y": tan() = opp/adj tan(22) = x/65 and tan(32) = (x + y)/65 We have a system of equations with two unknowns, so we can solve the first one for x, then substitute into the second and solve for y: tan(22) = x/65 x = 65 tan(22) tan(32) = (x + y)/65 Let's keep this here for now, solve for y in terms of x, then substitute: 65 tan(32) = x + y 65 tan(32) - x = y Substituting, we get: 65 tan(32) - 65 tan(22) = y or: 65 [tan(32) - tan(22)] = y Now using the calculator we can get approximations for tangents (rounding to 4-5 decimal places to limit errors due to rounding, then at the end, round to 1 DP as requested: y = 65(0.6249 - 0.4040) y = 65(0.2209) y = 14.3585 The distance between the points "R" and "S" is: 14.4 m
    1 answer · Mathematics · 2 weeks ago
  • X√9x^3 - 2√x^5?

    Best answer: I think you have: x√(9x³) - 2√(x⁵) We can factor out perfect squares from what's in the radical so we can eventually remove them from the radical: x√(9x² * x) - 2√(x⁴ * x) The root of a product is the same as the product of the roots, so: x√(9x²) * √(x) - 2√(x⁴) * √(x) Now the 9x² and the x⁴ are perfect squares inside of a... show more
    Best answer: I think you have: x√(9x³) - 2√(x⁵) We can factor out perfect squares from what's in the radical so we can eventually remove them from the radical: x√(9x² * x) - 2√(x⁴ * x) The root of a product is the same as the product of the roots, so: x√(9x²) * √(x) - 2√(x⁴) * √(x) Now the 9x² and the x⁴ are perfect squares inside of a square root, so they can be simplified: x(3x) * √(x) - 2x² * √(x) simplify further: 3x² √(x) - 2x² √(x) Both are x² √(x) terms, so we can combine like terms to get a coefficient of 1: x² √(x) Hope the explanation helps.
    3 answers · Mathematics · 2 weeks ago