• Can you plug a 230v appliance into a 240v outlet?

    Best answer: Normal home distribution is 120V/240V. In the old days people refer to these voltages as 110V/220V. Also as 115V/230V. Call SoCal Edison (if you are in California), or your electricity company, they may have an answer for you. Google 120 Volt US standard. http://www.straightdope.com/columns/read...
    Best answer: Normal home distribution is 120V/240V. In the old days people refer to these voltages as 110V/220V. Also as 115V/230V. Call SoCal Edison (if you are in California), or your electricity company, they may have an answer for you. Google 120 Volt US standard. http://www.straightdope.com/columns/read...
    2 answers · Other - Electronics · 10 years ago
  • How do you make a light bulb light with a potato?

    Best answer: I don't know about a potato, but with a copper plate and a zinc plate, separated by a thin piece of paper soaked with lemon juice, you could create a basic voltage cell. It may produce enough current to light up a bulb from a mini-flashlight. Make sure the plates don't become directly in contact with each other. I found... show more
    Best answer: I don't know about a potato, but with a copper plate and a zinc plate, separated by a thin piece of paper soaked with lemon juice, you could create a basic voltage cell. It may produce enough current to light up a bulb from a mini-flashlight. Make sure the plates don't become directly in contact with each other. I found these: http://mathinscience.info/teach/k5_scien... http://www.youtube.com/watch?v=ufoOJfzro... http://www.youtube.com/watch?v=YcEzVqbMF... http://www.how-things-work-science-projects.com/potato-battery.html
    2 answers · Engineering · 7 years ago
  • Simple speaker electronics project help..?

    Best answer: How does a speaker work?: First a simple speaker, not the ones for computers, those have an amplifier included in them. It has a Voice Coil surrounded by a Permanent Magnet. The voice coil ends are connected to a pair of terminals. If you connect a 1.5 V battery across the coil terminals, a current will circulate through the coil, and... show more
    Best answer: How does a speaker work?: First a simple speaker, not the ones for computers, those have an amplifier included in them. It has a Voice Coil surrounded by a Permanent Magnet. The voice coil ends are connected to a pair of terminals. If you connect a 1.5 V battery across the coil terminals, a current will circulate through the coil, and being under a magnetic field will cause the coil to displace. A cone is attached to the coil, so the cone will displace. If you now reverse the battery polarity, you will notice that the cone displaces in the opposite direction as it did before. The battery applies a DC (Direct Current) voltage to the speaker. An Audio Signal is an Alternating Current (AC). It changes polarity more or less rapidly according to the pitch (lows, medium, highs) of the sound. It applies higher or lower voltages according to the volume of the sound. Higher Volume = more cone displacement; Higher Pitch = more rapid cone vibrations. The majority of the speakers made to be used with computers, have an internal amplifier which needs to be connected a wall outlet. The Audio Signal is applied to a mini-jack receptacle on this speakers. Normally you would connect a cable from the Computer-Sound-Card's Line-out to the speakers. You also ask "What can I use as a recording module". You will need a microphone connected to the Computer-Sound-card's Line-in or Mic-in. Or the output of any other audio source. If you want more on that, email me.
    2 answers · Engineering · 7 years ago
  • Series regulator circuit?

    Best answer: The 20v output when loaded with 100Ω will draw 20/100= 200 mA. The 20v output when loaded with 1kΩ will draw 20/1k= 20 mA. We need 20mA for the Zenner and 200mA for the 100Ω load, a total of 220mA. The series resistor would be: (30v-20v)/220mA = 10/220 = ~46Ω When the load is 100Ω, there will be 20mA thru the Zenner, and when the load is... show more
    Best answer: The 20v output when loaded with 100Ω will draw 20/100= 200 mA. The 20v output when loaded with 1kΩ will draw 20/1k= 20 mA. We need 20mA for the Zenner and 200mA for the 100Ω load, a total of 220mA. The series resistor would be: (30v-20v)/220mA = 10/220 = ~46Ω When the load is 100Ω, there will be 20mA thru the Zenner, and when the load is 1kΩ there will be 200mA thru the Zenner. If the load becomes 10Ω, it would TRY to draw 20v/10Ω = 2000mA, but the drop on the series resistor would TRY to be V = 2000mA x 46Ω = 92v, but it couldn't because the input is only 30v, so the Zenner would not output 20v and would turn off. So what we have left with is a resistor divider, 46Ω in series with 10Ω. The voltage across the 10Ω would be 30v/(46Ω+10Ω) x 10Ω = 5.36v. So the 20v regulation is gone.
    1 answer · Engineering · 7 years ago
  • What store sells microphones other than walmart/target/radio shack?

    Best answer: Guitar Center.
    Best answer: Guitar Center.
    4 answers · Other - Electronics · 7 years ago
  • How can I become an expert in Electronics?

    Best answer: I would recommend taking courses in a Community College. Before you can call yourself an expert you have to acquire lots of knowledge and experience. This takes time, but eventually you'll get there. If you do not start, then you'll never get there. Also you could become an expert in one or more areas of electronics, like: Audio;... show more
    Best answer: I would recommend taking courses in a Community College. Before you can call yourself an expert you have to acquire lots of knowledge and experience. This takes time, but eventually you'll get there. If you do not start, then you'll never get there. Also you could become an expert in one or more areas of electronics, like: Audio; TV; Computers; Communications; etc. Another suggestion; visit http://en.wikipedia.org/wiki/Sound_recor... or any other subject of your choice. Read all about it, then click on the links (text in blue), read about all relating subjects. Don't let difficult to understand topics bother you, skip them, keep reading what you can understand.
    1 answer · Other - Electronics · 7 years ago
  • Can anyone tell me where I can find the power consumption...?

    Best answer: The consumption should be in the label plate located on the back of the unit (how convenient). If you have the User's manual, may be there also, but I doubt it. If you are really interested, look at your electric meter when the machine is running (at different cycles). Be sure you have no additional devices or light bulbs on. Count... show more
    Best answer: The consumption should be in the label plate located on the back of the unit (how convenient). If you have the User's manual, may be there also, but I doubt it. If you are really interested, look at your electric meter when the machine is running (at different cycles). Be sure you have no additional devices or light bulbs on. Count the turns of the meter's disk for at least one minute. With that and knowing the meter's constant (Google for that info) you could determine the power it's consuming. If that's too complicated, go to Home Depot and buy a power meter for about $25. Plug that on the wall, and plug the machine into it. It has a digital display. You could also look at the spec's online for that machine: http://www.speedqueen.com/
    1 answer · Other - Electronics · 10 years ago
  • Is a 17 watt computer speaker system enough for my bedroom?

    Best answer: 17 watts would either be the rating for the amp or the max power handling of the speakers, but most likely for the amp. Different speakers have different efficiencies. Higher Efficiency means that it will produce a higher Acoustic Output with the same Input Power supplied by the amp. Speaker efficiencies vary from 87 to 101 dB SPL... show more
    Best answer: 17 watts would either be the rating for the amp or the max power handling of the speakers, but most likely for the amp. Different speakers have different efficiencies. Higher Efficiency means that it will produce a higher Acoustic Output with the same Input Power supplied by the amp. Speaker efficiencies vary from 87 to 101 dB SPL (this is when 1 Watt is applied to them, and measured at 1 meter distance). Every time you double the power you get 3 dB more, so for an 87 dB speaker you'll get 90 dB at 2 W, 93 at 4 W, 96 at 8 W and 99 at 16 W. Compare that to what you get with the 101 dB SPL speaker at just only 1 W. So, it is very hard to tell how much Acoustic output (Loudness or Volume) you'll get with your speakers, unless they are properly specified. The other factor is "how much volume do you, you personally, need". Not all of us perceive equally what is low, medium, high or too-high volume. This is the reason for which to properly compare sound levels, we should use dB SPL.
    2 answers · Other - Electronics · 10 years ago
  • How to test coil, if possible?

    Best answer: The coil has a Primary and a Secondary. When the rotor opens the connection to the Primary, a very high voltage (thousands of volts) develops on the Secondary. The Primary winding may have common connection to the Secondary, but this is just the way they are built. You could measure the winding continuity with a multimeter, but you may... show more
    Best answer: The coil has a Primary and a Secondary. When the rotor opens the connection to the Primary, a very high voltage (thousands of volts) develops on the Secondary. The Primary winding may have common connection to the Secondary, but this is just the way they are built. You could measure the winding continuity with a multimeter, but you may get a spark that may ruin the meter. Just verify that the contact opens and closes. Generally there is a capacitor connected across the contacts (points), if it is shorted, then you'll never get a spark. Disconnect it temporarily, it is there to avoid noise getting into your radio and points wear. Remove the Center Distributor Hi-Voltage wire and bring close to chassis, as you crank the ignition. If you have a spark there, then you may have a defective distributor rotor. Read this: http://en.wikipedia.org/wiki/Distributor
    2 answers · Engineering · 9 years ago
  • Would a monoblock amplifier be the same thing as a 2 channel amplifier bridged?

    Best answer: As far as I know, a Mono-block amp is just a Single Channel Amp. If a Stereo Amp has the capability to be connected in Bridge Mode (not all do), then one of its two channels is set to Invert respect to the other. Doing this and connecting the load across the two hot outputs, the load will have twice the voltage output applied to it.... show more
    Best answer: As far as I know, a Mono-block amp is just a Single Channel Amp. If a Stereo Amp has the capability to be connected in Bridge Mode (not all do), then one of its two channels is set to Invert respect to the other. Doing this and connecting the load across the two hot outputs, the load will have twice the voltage output applied to it. Power = Volts^2/Zo (Zo is the speaker nominal impedance). Example: for 8 Volts, V^2=64, if Zo=8 Ohms, then P=64/8=8 Watts. If you double the voltage P=16^2/Zo=256/8=32 watts. Now, each amp channel "sees" 4 Ohms, so you have to be careful about using 4 Ohms speakers in bridge mode, each channel will "see" 2 Ohms. Verify that the amp can handle it.
    2 answers · Other - Electronics · 9 years ago
  • How can i change my comp screen from 720p to 1080p?

    Best answer: The resolution setting for 1080p is 1920x1080. Some TVs refresh at 60Hz, others at 120Hz. The specs on your TV should indicate what yours is.
    Best answer: The resolution setting for 1080p is 1920x1080. Some TVs refresh at 60Hz, others at 120Hz. The specs on your TV should indicate what yours is.
    1 answer · Monitors · 10 years ago
  • How to convert to Excel formula?

    Best answer: I'll give you the independent entries, then you combine them. For π you enter > =PI() For Cosine > =COS(angle in radians) For Sine > =SIN(angle in radians). If you need to convert to degrees, then enter > =SIN(PI()/180*angle in degrees) For Square Root > =SQRT(number) Try independent examples, like =PI() to get... show more
    Best answer: I'll give you the independent entries, then you combine them. For π you enter > =PI() For Cosine > =COS(angle in radians) For Sine > =SIN(angle in radians). If you need to convert to degrees, then enter > =SIN(PI()/180*angle in degrees) For Square Root > =SQRT(number) Try independent examples, like =PI() to get 3.141593 If you mean: 1/4π0.09^2 to be the product of 3 terms, then separate them by an "*" > =1/4*PI()*0.09^2 Do not use brackets "[ ]", but parenthesis "( )" You may find it easier to separate the whole equation into parts: On cell A1 enter =0.000045; on A2 enter =1/4*PI()*0.09^2; etc. Then combine all parts into A9 =A1+A2+A3..... Let me know if you need more help. Email me.
    3 answers · Engineering · 7 years ago
  • What will be the weight of 8mm x 4 meter x 1.51 meter of 304 steel slab?

    Best answer: Let's start knowing that the Density of 304 Steel is 7.75 grams/cm^3 Now, let's calculate how many cm^3 are in the steel slab: 8 mm = 0.8 cm; 4 m = 40 cm; 1.51 m = 15.1 cm So we have 0.8 x 40 x 15.1 = 483.2 cm^3 7.75 grams/cm^3 x 483.2 cm^3 = 3,744.8 grams or 3.7448 kilograms
    Best answer: Let's start knowing that the Density of 304 Steel is 7.75 grams/cm^3 Now, let's calculate how many cm^3 are in the steel slab: 8 mm = 0.8 cm; 4 m = 40 cm; 1.51 m = 15.1 cm So we have 0.8 x 40 x 15.1 = 483.2 cm^3 7.75 grams/cm^3 x 483.2 cm^3 = 3,744.8 grams or 3.7448 kilograms
    2 answers · Engineering · 8 years ago
  • What is the difference between low frequency and high frequency in sound.?

    Best answer: The audible frequency range for humans is from 20 Hz to 20,000 Hz. As you get older your sensitivity towards the high end is diminished. You could divide the full range into 3 sections: 20-300 (low); 300-5,000 (mid) and 5,000 to 20,000 (high).
    Best answer: The audible frequency range for humans is from 20 Hz to 20,000 Hz. As you get older your sensitivity towards the high end is diminished. You could divide the full range into 3 sections: 20-300 (low); 300-5,000 (mid) and 5,000 to 20,000 (high).
    4 answers · Engineering · 8 years ago
  • I cannot get all 5 speakers to be in "on" mode, only the front two?

    Best answer: Make sure that the "source" of the sound is DD 5.1. Example: Optical (or coaxial) output of a DVD Player playing a movie with 5.1 sound in it. The Red and White RCA output from the DVD Player only carry Stereo, not DD 5.1. You need 5.1 to get surround sound through all 5 speakers+sub-woofer.
    Best answer: Make sure that the "source" of the sound is DD 5.1. Example: Optical (or coaxial) output of a DVD Player playing a movie with 5.1 sound in it. The Red and White RCA output from the DVD Player only carry Stereo, not DD 5.1. You need 5.1 to get surround sound through all 5 speakers+sub-woofer.
    2 answers · Home Theatre · 7 years ago
  • How does the number of coils of wire in an electromagnet affect its magnetic strength?

    Best answer: The Magnetic Field Strength is proportional to the Number of Turns of the winding. The basic equation is: Φ ≈ N * I, where Φ is the Flux or Magnetic Field Strength, N is the Number of Turns of the winding and I is the current through the winding. The Magnetic material (the Core) also affects the Flux, but if you keep that constant, then... show more
    Best answer: The Magnetic Field Strength is proportional to the Number of Turns of the winding. The basic equation is: Φ ≈ N * I, where Φ is the Flux or Magnetic Field Strength, N is the Number of Turns of the winding and I is the current through the winding. The Magnetic material (the Core) also affects the Flux, but if you keep that constant, then the Flux will change only according to the Turns and Current. Like the other answerer said; "Provided you do not saturate the Core". See this: http://www.learnabout-electronics.org/ac...
    3 answers · Engineering · 6 years ago
  • Can you use a 7.5V Ac Adapter to charge a 6V battery?

    Best answer: Basically you could. To charge a battery the charger has to have a voltage higher than that of the battery. The only requirement is to have current (amps) limitation. This is obtained with a resistor in series, but if your charger has an internal resistance then you don't need it. Another question is: for how long would you leave it... show more
    Best answer: Basically you could. To charge a battery the charger has to have a voltage higher than that of the battery. The only requirement is to have current (amps) limitation. This is obtained with a resistor in series, but if your charger has an internal resistance then you don't need it. Another question is: for how long would you leave it to charge?
    2 answers · Other - Electronics · 9 years ago
  • Voltage Checker Correction?

    Best answer: The way to check a battery is with a small load, close to the normal current that needs to supply during normal usage. If you know how much the phone consumes, connect a resistor across the battery so it draws current while you measure its voltage. Without load you couldn't be sure of its charge. If the terminals are accessible,... show more
    Best answer: The way to check a battery is with a small load, close to the normal current that needs to supply during normal usage. If you know how much the phone consumes, connect a resistor across the battery so it draws current while you measure its voltage. Without load you couldn't be sure of its charge. If the terminals are accessible, you could try to measure it as it is in the phone when is turned on.
    4 answers · Engineering · 9 years ago
  • Transformer/Electromagnetism question?

    Best answer: Although i don't know this well, since you have received no answers, I will try to answer. Let's say that the whole stack contains 50 laminations, and has an overall thickness of 25mm. If the stacking factor were 1.00, then each lamination would be 25mm/50 = 0.5mm. With a 0.94 factor the max number of laminations would be reduced... show more
    Best answer: Although i don't know this well, since you have received no answers, I will try to answer. Let's say that the whole stack contains 50 laminations, and has an overall thickness of 25mm. If the stacking factor were 1.00, then each lamination would be 25mm/50 = 0.5mm. With a 0.94 factor the max number of laminations would be reduced to: (25mm x 0.94) / 0.5mm = 23.5 / 0.5 = 47 laminations. The reason the stacking factor is less than 1 is because each lamination has a very thin layer of insulation (on each side) and also they are not perfectly flat, so you couldn't pack them so tightly. When you purchase the laminations, you would have a few choices of thicknesses, depending on the core dimensions. ADDED: I understand that you have a core with its dimensions. You have also selected a lamination vendor, so you would have the lamination thicknesses available. When calculating the Inductor or Transformer you would determine the stack dimension from the core area needed given the EI dimensions. You would then use the 0.94 factor to determine how much extra laminations you'll need to compensate for the thickness loss due to lamination insulation, etc. Keep in touch, email me, I hope I could help you. If you rather keep the stack dimension constant, the you can use the 0.94 factor as a factor that reduces the effective lamiantion thickness. In my first example, 0.5mm x 0.94 = 0.47mm. Then use 0.47mm to calculate Eddy losses. This site has good info related to Eddy Current Losses: http://info.ee.surrey.ac.uk/Workshop/adv... A similar question somebody asked on Yahoo Answers: http://answers.yahoo.com/question/index?...
    1 answer · Engineering · 7 years ago
  • How do I calculate scale on engineering copy?

    Best answer: Multiply the dimension of the door by 0.125 (or 1/8); 4' x 0.125" is equivalent to 0.5" (or 1/2"). Draw a segment 0.5" long. Use the same multiplier for any other dimension.
    Best answer: Multiply the dimension of the door by 0.125 (or 1/8); 4' x 0.125" is equivalent to 0.5" (or 1/2"). Draw a segment 0.5" long. Use the same multiplier for any other dimension.
    3 answers · Engineering · 9 years ago