• Do you think that the next year will come with the new video game consoles ?

    I think that we may see announcements for the next generation of XBO and PS4 in 2019, but I don't think that either will be released until 2020.
    I think that we may see announcements for the next generation of XBO and PS4 in 2019, but I don't think that either will be released until 2020.
    1 answer · Video & Online Games · 57 mins ago
  • Does anyone else find the power button on the switch hard to press?

    Who turns off their Switch? Mine lives in sleep mode when I'm not playing it.
    Who turns off their Switch? Mine lives in sleep mode when I'm not playing it.
    1 answer · Video & Online Games · 3 hours ago
  • Precalc question: can anyone pls check my answer to this equation,?

    Based on the answers given in your other question about this, (3, 3) is not the correct answer.
    Based on the answers given in your other question about this, (3, 3) is not the correct answer.
    3 answers · Mathematics · 5 hours ago
  • Can I have some help with this math problem, please?

    You are solving for the height of the plant at 8 weeks, to get the rate of the growth at 8 week, you have to solve for the first derivative and solve for when that function's x = 8. f(t) = 0.3t² + 0.6t + 0.5 f'(t) = 0.6t + 0.6 f'(t) = 0.6(t + 1) f'(8) = 0.6(8 + 1) f'(8) = 0.6(9) f'(8) = 5.4 inches/week show more
    You are solving for the height of the plant at 8 weeks, to get the rate of the growth at 8 week, you have to solve for the first derivative and solve for when that function's x = 8. f(t) = 0.3t² + 0.6t + 0.5 f'(t) = 0.6t + 0.6 f'(t) = 0.6(t + 1) f'(8) = 0.6(8 + 1) f'(8) = 0.6(9) f'(8) = 5.4 inches/week
    7 answers · Mathematics · 7 hours ago
  • Help me sketch this graph pls: 2x-y=-4?

    Best answer: There are many ways to go. One way is to solve for the intercepts. Solve for x when y = 0 and solve for y when x = 0. That will give you two points. Then connect the points and you have your line: 2x - y = -4 2(0) - y = -4 and 2x - 0 = -4 0 - y = -4 and 2x = -4 -y = -4 and x = -2 y = 4 and x = -2 So your points are: (0, 4) and... show more
    Best answer: There are many ways to go. One way is to solve for the intercepts. Solve for x when y = 0 and solve for y when x = 0. That will give you two points. Then connect the points and you have your line: 2x - y = -4 2(0) - y = -4 and 2x - 0 = -4 0 - y = -4 and 2x = -4 -y = -4 and x = -2 y = 4 and x = -2 So your points are: (0, 4) and (-2, 0) Plot the points and connect the points.
    8 answers · Mathematics · 12 hours ago
  • Math hw. Highschool second year logarithms and exponent functions?

    I don't think this is a logarithm problem. We know the total cost of the bus rental is 1440€. This is to be split up between all of the students (unknown), so the cost per student is: 1440 / x 4 Students cancel resulting in students having to pay 5€ more, so if the above is the cost per student before the cancellation, the new cost per... show more
    I don't think this is a logarithm problem. We know the total cost of the bus rental is 1440€. This is to be split up between all of the students (unknown), so the cost per student is: 1440 / x 4 Students cancel resulting in students having to pay 5€ more, so if the above is the cost per student before the cancellation, the new cost per student is: 1440 / (x - 4) And this is 5€ more than original, so we can add 5 to the original to make a balanced equation: 5 + 1440 / x = 1440 / (x - 4) Now many students are going? It doesn't say "originally" or "after the cancellations", but if we solve for x we will get the "original" value, then we can subtract 4 to get the "after" value. LCD is x(x - 4), so multiply both sides by this LCD: 5x(x - 4) + 1440(x - 4) = 1440x Simplify to a quadratic: 5x² - 20x + 1440x - 5760 = 1440x Subtract 1440x from both sides: 5x² - 20x - 5760 = 0 divide both sides by 5: x² - 4x - 1152 = 0 I'll complete the square for this, so I'll add 1152 to both sides, then add 4 more: x² - 4x = 1152 x² - 4x + 4 = 1156 (x - 2)² = 1156 x - 2 = ±34 x = 2 ± 34 We can't have a negative number of students, so: x = 2 + 34 x = 36 36 students originally signed up for the trip but only 32 students went on it.
    3 answers · Mathematics · 13 hours ago
  • P( -1.5< z < 0.5) = how do i solve it?

    Using a z-table, You can get the probability of a random data point (in a normally distributed dataset) to be less than that point. So if you find: P(z < 0.5) And: P(z < -1.5) Then subtract the two (the overlap) you get the range in between the points. So we have: P(z < 0.5) - P(z < -1.5) Using the z-score table linked below, we... show more
    Using a z-table, You can get the probability of a random data point (in a normally distributed dataset) to be less than that point. So if you find: P(z < 0.5) And: P(z < -1.5) Then subtract the two (the overlap) you get the range in between the points. So we have: P(z < 0.5) - P(z < -1.5) Using the z-score table linked below, we get: 0.6915 - 0.0668 0.6247
    1 answer · Mathematics · 14 hours ago
  • What is 6 to the power 3+5(8+1/5)?

    If you mean: 6³ + 5(8 + 1/5) Then first I'll simplify the exponent and add the fraction: 216 + 5(40/5 + 1/5) 216 + 5(41/5) Now we can multiply (the 5's cancel): 216 + 41 And finally, add: 257
    If you mean: 6³ + 5(8 + 1/5) Then first I'll simplify the exponent and add the fraction: 216 + 5(40/5 + 1/5) 216 + 5(41/5) Now we can multiply (the 5's cancel): 216 + 41 And finally, add: 257
    7 answers · Mathematics · 14 hours ago
  • Given that m and n are digits, what is the sum of the values of m and n such that the five-digit number m6,79n is divisible by 72?Show work.?

    Let's break down 72 to see what the prime factorizations are: 72 = 2³ * 3² So it has to be both divisible by 9 and divisible by 8. Because 1000 is divisible by 8, any number is divisible by 8 if the last 3 digits are divisible by 8. Since we know two digits are 7 and 9, we only have a few values to test to see if this is divisible by 8. ... show more
    Let's break down 72 to see what the prime factorizations are: 72 = 2³ * 3² So it has to be both divisible by 9 and divisible by 8. Because 1000 is divisible by 8, any number is divisible by 8 if the last 3 digits are divisible by 8. Since we know two digits are 7 and 9, we only have a few values to test to see if this is divisible by 8. 792 is the only 3-digit number starting with 79 that is divisible by 8. Therefore n must be 2. Now to be divisible by 9, the sum of the digits must also be divisible by 9. Let's add up what we know and see what we have: m + 6 + 7 + 9 + 2 m + 24 To make this divisible by 9, we need the sum to be 27, so m = 3. Now that we know what m and n are, we can find the sum: m + n 3 + 2 5
    2 answers · Mathematics · 1 day ago
  • How do I simplify radicals as such?

    √12 / √9 The square root of 9 simplifies itself: √12 / 3 Then we can factor out a 4 from the 12 which then can be pulled out of the square root: √(4 * 3) / 3 2√3 / 3 or: (2/3)√3
    √12 / √9 The square root of 9 simplifies itself: √12 / 3 Then we can factor out a 4 from the 12 which then can be pulled out of the square root: √(4 * 3) / 3 2√3 / 3 or: (2/3)√3
    11 answers · Mathematics · 2 days ago
  • Should i play minecraft and not play any other game until i finish the entire game and kill all the bosses? Answer before 20.12.2018?

    I don't think that you understand what Minecraft is.
    I don't think that you understand what Minecraft is.
    4 answers · Video & Online Games · 2 days ago
  • The half-life of cobalt-60 is 5.27 years. approximately how much of a 199 g sample will remain after 20 yrs?

    While there are more streamlined equations knowing it's a half-life equation, I still like to use this general equation for growth/decay problems and work out the constant for myself: a(t) = ae^(kt) Where: a = initial amount (when t = 0) t = time after the initial moment (can be any time frame as long as you are consistent with your times --... show more
    While there are more streamlined equations knowing it's a half-life equation, I still like to use this general equation for growth/decay problems and work out the constant for myself: a(t) = ae^(kt) Where: a = initial amount (when t = 0) t = time after the initial moment (can be any time frame as long as you are consistent with your times -- can't talk minutes and then years in the same problem) k = decay constant So first we need to solve for the decay constant. We can start with any starting amount and then half it with time = 5.27 years, so let's solve for k using these variables: a(5.27) = 0.5 a = 1 That gives us: a(t) = ae^(kt) a(5.27) = 1e^(k * 5.27) 0.5 = e^(5.27k) ln(0.5) = 5.27k k = ln(0.5) / 5.27 so now our equation becomes: a(t) = ae^(kt) a(t) = ae^(t ln(0.5) / 5.27) a(t) = ae^(t ln(0.5) / 5.27) So given the initial amount of 199 g, what's left after 20 years? Solve using a = 199 and t = 20: a(t) = 199e^(20 ln(0.5) / 5.27) a(t) = 199e^(20(-0.69315) / 5.27) While I'm rounding here, I'm not in my calculator to reduce errors due to rounding: a(t) = 199e^(-13.86294 / 5.27) a(t) = 199e^(-2.63054) a(t) = 199(0.07204) a(t) = 14.336 g (rounded to 3DP) will remain after 20 years. As a quick estimate, 20 years is a little less than 4 half-lives, so if we half the initial amount 4 times we will have something close: 199 / 2 = 99.5 99.5 / 2 = 49.75 49.75 / 2 = 24.875 24.875 / 2 = 12.4375 They are reasonably close, so we can be confident in the calculated result, which again was: 14.336 g
    4 answers · Mathematics · 2 days ago
  • Gamer challenge?

    Pong
    Pong
    3 answers · Video & Online Games · 2 days ago
  • Need help with this math words problem How much money did Carla take out of the bank?

    Best answer: Look at smaller numbers: From 1-5 is obviously 5 numbers. But if you subtract them you get 4. When subtracting numbers, the original number gets counted but the top number doesn't, so you have to add 1 to it to count that missed number.
    Best answer: Look at smaller numbers: From 1-5 is obviously 5 numbers. But if you subtract them you get 4. When subtracting numbers, the original number gets counted but the top number doesn't, so you have to add 1 to it to count that missed number.
    3 answers · Mathematics · 2 days ago
  • Is it possible for me to get an A in this class if i get an A on the final? (my current grades by category are below)?

    Let's see what we get. Using the break-down you provided as weights we can weight each grade using the final as an unknown and see what is needed to get a 90 overall: 0.15 * 77.59 + 0.1 * 44.44 + 0.05 * 88 + 0.3 * 90 + 0.1 * 100 + 0.3x = 90 11.6385 + 4.444 + 4.4 + 27 + 10 + 0.3x = 90 57.4825 + 0.3x = 90 0.3x = 32.5175 x = 32.5175 / 0.3 x =... show more
    Let's see what we get. Using the break-down you provided as weights we can weight each grade using the final as an unknown and see what is needed to get a 90 overall: 0.15 * 77.59 + 0.1 * 44.44 + 0.05 * 88 + 0.3 * 90 + 0.1 * 100 + 0.3x = 90 11.6385 + 4.444 + 4.4 + 27 + 10 + 0.3x = 90 57.4825 + 0.3x = 90 0.3x = 32.5175 x = 32.5175 / 0.3 x = 108.392 So unless you can get over 108% on the final, you cannot get an A.
    4 answers · Mathematics · 2 days ago
  • Where can I find the game everquest for PC that's relatively cheap? Does it come on any other platform?

    You can download the game client from everquest.com and play up to I think Level 85 for free. After that you have to pay for their All-Access (about $15 a month?) to continue past that. The game is for Windows, only. I believe that the free content is only the base game before any expansions (the 25th expansion just launched the other day). If... show more
    You can download the game client from everquest.com and play up to I think Level 85 for free. After that you have to pay for their All-Access (about $15 a month?) to continue past that. The game is for Windows, only. I believe that the free content is only the base game before any expansions (the 25th expansion just launched the other day). If you choose to buy the latest expansion, you get all previous expansions with it.
    1 answer · Video & Online Games · 2 days ago
  • How do you rationalize the expression?

    I think you mean: (5√2 - 2√5) / (√2 - √5) To rationalize the denominator, multiply both halves by the denominator's conjugate which is (√2 + √5): (5√2 - 2√5)(√2 + √5) / [(√2 - √5)(√2 + √5)] Now expand both halves. The denominator will be rational at the end: (5 * 2 + 5√10 - 2√10 - 2 * 5) / (2 + √10 - √10 - 5) (10 + 5√10 - 2√10 - 10) / (2... show more
    I think you mean: (5√2 - 2√5) / (√2 - √5) To rationalize the denominator, multiply both halves by the denominator's conjugate which is (√2 + √5): (5√2 - 2√5)(√2 + √5) / [(√2 - √5)(√2 + √5)] Now expand both halves. The denominator will be rational at the end: (5 * 2 + 5√10 - 2√10 - 2 * 5) / (2 + √10 - √10 - 5) (10 + 5√10 - 2√10 - 10) / (2 + √10 - √10 - 5) (5√10 - 2√10) / (2 - 5) (3√10) / (-3) Cancel out the 3's and move the negative to the numerator: (√10) / (-1) -√10 Which is oddly enough the same problem I solved 4 days ago and got the same answer: https://answers.yahoo.com/question/index...
    2 answers · Mathematics · 2 days ago
  • An aluminum company has hired you to design a cylindrical can. You are given expressions for both the radius, (5-x)cm, and the height, (2x+1?

    Volume of a cylinder is: V = πr²h You are given an expression for radius and height as: r = 5 - x h = 2x + 1 The radius has to be greater than zero, so x must be smaller than 5. The height must be greater than zero, so x must be larger than -1/2. So the domain restrictions are: -1/2 < x < 5 If we substitute both expressions into the... show more
    Volume of a cylinder is: V = πr²h You are given an expression for radius and height as: r = 5 - x h = 2x + 1 The radius has to be greater than zero, so x must be smaller than 5. The height must be greater than zero, so x must be larger than -1/2. So the domain restrictions are: -1/2 < x < 5 If we substitute both expressions into the volume equation we will have volume in terms of x: V = πr²h V = π(5 - x)²(2x + 1) Simplify: V = (25 - 10x + x²)(2x + 1)π V = (50x + 25 - 20x² - 10x + 2x³ + x²)π V = (40x + 25 - 19x² + 2x³)π V = (2x³ - 19x² + 40x + 25)π Now here is where I'm not sure how to find the max value without using calculus. If this was a quadratic we could do it, but not sure about a cubic. So maybe someone else will have an idea on how to do that. So I can find the "x" needed to get a maximum Volume by solving for the zero of the first derivative knowing the limits of x as explained above. I'll distribute π to every term and treat it as part of the coefficients as a constant (because it is): V = 2πx³ - 19πx² + 40πx + 25π First derivative: V' = 6πx² - 38πx + 40π Solve for zero: 0 = 6πx² - 38πx + 40π First I'll divide both sides by 2π to simplify. Then I'll use the quadratic equation: 0 = 3x² - 19x + 20 x = [ -b ± √(b² - 4ac)] / (2a) x = [ -(-19) ± √((-19)² - 4(3)(20))] / (2 * 3) x = [ 19 ± √(361 - 240)] / 6 x = [ 19 ± √(121)] / 6 x = (19 ± 11) / 6 x = 8/6 and 30/6 x = 4/3 and 5 Since we know that x must be smaller than 5 we can throw that out: x = 4/3 So at x = 4/3, the volume is at a maximum: V = (2x³ - 19x² + 40x + 25)π V = [2(4/3)³ - 19(4/3)² + 40(4/3) + 25]π V = [2(64/27) - 19(16/9) + 40(4/3) + 25]π V = (128/27 - 304/9 + 160/3 + 25)π V = (128/27 - 912/27 + 1440/27 + 675/27)π V = (1331/27)π cm³ or approx: 154.87 cm³ (rounded to 2DP)
    5 answers · Mathematics · 2 days ago
  • Find terms of an arithmetic series?

    I use this expression as the general form for the n'th term of an arithmetic sequence: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. The sum of the first "n" terms of a sequence is the sum of the first and last terms, multiplied by the number of terms, divided by 2, or: S(n) = [a + a(n)]n /... show more
    I use this expression as the general form for the n'th term of an arithmetic sequence: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. The sum of the first "n" terms of a sequence is the sum of the first and last terms, multiplied by the number of terms, divided by 2, or: S(n) = [a + a(n)]n / 2 Let's substitute the a(n) expression here and simplify: S(n) = [a + a + b(n - 1)]n / 2 S(n) = (2a + bn - b)n / 2 S(n) = (2an + bn² - bn) / 2 We are told that S(10) = 210 and S(20) = 820. So using the equation above, substitute what we know and we'll get a system of two equations and two unknowns (a and b) that we can solve for: S(n) = (2an + bn² - bn) / 2 S(10) = (2a * 10 + b * 10² - b * 10) / 2 and S(20) = (2a * 20 + b * 20² - b * 20) / 2 S(10) = (20a + 100b - 10b) / 2 and S(20) = (40a + 400b - 20b) / 2 S(10) = (20a + 90b) / 2 and S(20) = (40a + 380b) / 2 S(10) = 10a + 45b and S(20) = 20a + 190b Now we can substitute the values for S(10) and S(20) and simplify: 210 = 10a + 45b and 820 = 20a + 190b Solve the first equation for a in terms of b, then substitute: 210 = 10a + 45b 210 - 45b = 10a 21 - 4.5b = a 820 = 20a + 190b 820 = 20(21 - 4.5b) + 190b 820 = 420 - 90b + 190b 400 = 100b b = 4 Now we can solve for a: a = 21 - 4.5b a = 21 - 4.5(4) a = 21 - 18 a = 3 Now we know the first term is 3 and the common difference is 4. So the first 5 terms are: 3, 7, 11, 15, 19
    5 answers · Mathematics · 2 days ago
  • Find f. f ''(x) = −2 + 30x − 12x2, f(0) = 8, f '(0) = 18?

    You are told the following: f"(x) = -2 + 30x - 12x² f(0) = 8 f'(0) = 18 As you integrate the double-derivative function to find the original function you generate new constant terms that are initially known. The second two parts pretty much tell you what those constants are. So first, I'm going to put that function into standard... show more
    You are told the following: f"(x) = -2 + 30x - 12x² f(0) = 8 f'(0) = 18 As you integrate the double-derivative function to find the original function you generate new constant terms that are initially known. The second two parts pretty much tell you what those constants are. So first, I'm going to put that function into standard polynomial order, then integrate twice to get the original function: f"(x) = -12x² + 30x - 2 For each term, I'll add 1 to the exponent, divide the coefficient by the new exponent to get the new coefficient then add the constant term at the end: f'(x) = -4x³ + 15x² - 2x + k Since we were told that f'(0) = 18, we know that's what k is: f'(x) = -4x³ + 15x² - 2x + 18 Now do this one more time: f(x) = -x⁴ + 5x³ - x² + 18x + k And again, f(0) = 8, so: f(x) = -x⁴ + 5x³ - x² + 18x + 8 That's your function.
    3 answers · Mathematics · 2 days ago