• Hlw.if i give my ps4 account email and pass to my frnd..can he play my games and can he use my ps plus?can we play together.?

    I don't think you can both play the same game from your account at the same time. Your account only has one license to play the game. If you are already playing it, then he won't be able to. He would have to buy his own license and PS Plus for the two of you two play together.
    I don't think you can both play the same game from your account at the same time. Your account only has one license to play the game. If you are already playing it, then he won't be able to. He would have to buy his own license and PS Plus for the two of you two play together.
    2 answers · Video & Online Games · 12 hours ago
  • Advice on Bluetooth connectors for PC?

    They have cheap USB devices that you can put in your computer to give it Bluetooth capabilities. Here is an example for under $10: https://amzn.to/2KfqN7t
    They have cheap USB devices that you can put in your computer to give it Bluetooth capabilities. Here is an example for under $10: https://amzn.to/2KfqN7t
    2 answers · PC · 13 hours ago
  • Why is it that when I calculated for volume of sphere, the pi was not included in the calculation? The answer still had the pi uncalculated.?

    I agree with Morningfox. Unless told to use an approximation for π, leave the answer in terms of π. So your equation looks like this: V = (4/3)πr³ Where r = 2, we get: V = (4/3)π(2)³ V = (4/3)π(8) V = (32/3)π cm³
    I agree with Morningfox. Unless told to use an approximation for π, leave the answer in terms of π. So your equation looks like this: V = (4/3)πr³ Where r = 2, we get: V = (4/3)π(2)³ V = (4/3)π(8) V = (32/3)π cm³
    8 answers · Mathematics · 24 hours ago
  • Need help with this math problem?

    Best answer: What rational expression do you get when you combine the two chemicals? They want you to solve for: C1(x) + C2(x) Since we know that: C1(x) = x / (x + 1) and C2(x) = 2 / (x - 3) We can substitute and simplify: C1(x) + C2(x) x / (x + 1) + 2 / (x - 3) Get a common denominator: x(x - 3) / [(x + 1)(x - 3)] + 2(x + 1) / [(x + 1)(x -... show more
    Best answer: What rational expression do you get when you combine the two chemicals? They want you to solve for: C1(x) + C2(x) Since we know that: C1(x) = x / (x + 1) and C2(x) = 2 / (x - 3) We can substitute and simplify: C1(x) + C2(x) x / (x + 1) + 2 / (x - 3) Get a common denominator: x(x - 3) / [(x + 1)(x - 3)] + 2(x + 1) / [(x + 1)(x - 3)] Now we can add the numerators: [x(x - 3) + 2(x + 1)] / [(x + 1)(x - 3)] And simplify each half: (x² - 3x + 2x + 2) / (x² - 3x + x - 3) (x² - x + 2) / (x² - 2x - 3) so: C1(x) + C2(x) = (x² - x + 2) / (x² - 2x - 3) That's the answer to part a. What's the simplified equation? So we take the above and multiply it by H(x), which is: H(x) = (x³ - 9x) / x That in itself can be simplified to: H(x) = x² - 9 So if we multiply the result from part "a" by this we get the simplified result for V(x) (answer to part "b"): V(x) = [C1(x) + C2(x)] * H(x) Substitute what we know: V(x) = (x² - x + 2) / (x² - 2x - 3) * (x² - 9) Recall that the denominator can be factored, of which (x - 3) is a factor. (x² - 9) is the difference of two squares, so that can be factored: V(x) = (x² - x + 2) / [(x + 1)(x - 3)] * (x + 3)(x - 3) The (x - 3)'s cancel out, leaving: V(x) = (x² - x + 2) / (x + 1) * (x + 3) Now we can multiply the numerators and simplify: V(x) = (x² - x + 2)(x + 3) / (x + 1) V(x) = (x³ + 3x² - x² - 3x + 2x + 6) / (x + 1) V(x) = (x³ + 2x² - x + 6) / (x + 1) (x + 1) isn't a factor of this numerator, so this is the answer to part "b". So now you just have to solve for V(50), V(100), and V(1000). I'll do the first one, you can do the others following the same steps: V(x) = (x³ + 2x² - x + 6) / (x + 1) V(50) = (50³ + 2(50)² - 50 + 6) / (50 + 1) V(50) = (125000 + 2(2500) - 44) / 51 V(50) = (125000 + 5000 - 44) / 51 V(50) = 129956 / 51 unit³ (approx 2548.16 unit³) ---- If you need a volume of 3000, how many units do you need? V(x) = 3000, so now we can solve for x: V(x) = (x³ + 2x² - x + 6) / (x + 1) 3000 = (x³ + 2x² - x + 6) / (x + 1) Multiply both sides by the denominator: 3000(x + 10) = x³ + 2x² - x + 6 Expand and simplify: 3000x + 30000 = x³ + 2x² - x + 6 0 = x³ + 2x² - 3001x - 29994 Solving this is its own challenge. Looking at the graph, there are three real roots, two of them negative, so we can throw them out. The final root is near 60, so if you know Newton's method, we can start from there and iterate a few times to determine that the positive root of this function is at: x ≈ 58.3
    1 answer · Mathematics · 1 day ago
  • 'Insert a PS Vita card that contains this application'?

    You can't just give games to someone using the Vita cards. The PSN account used to sign into the machine still has to have the license to play the game. Unless you mean the actual cartridge vs. the memory card, this can't happen.
    You can't just give games to someone using the Vita cards. The PSN account used to sign into the machine still has to have the license to play the game. Unless you mean the actual cartridge vs. the memory card, this can't happen.
    1 answer · Video & Online Games · 1 day ago
  • Urgent Math question, help please!?

    Your are given the equation: A(t) = A₀e^(kt) Where A₀ is the population when t = 0 A(t) is the population in "t" years and k is the decay constant for this equation (our initial unknown) The whole "5 years ago" thing makes it confusing since we don't know when this problem was written. So we can't really answer this... show more
    Your are given the equation: A(t) = A₀e^(kt) Where A₀ is the population when t = 0 A(t) is the population in "t" years and k is the decay constant for this equation (our initial unknown) The whole "5 years ago" thing makes it confusing since we don't know when this problem was written. So we can't really answer this since we don't know what year is 0 year other than it's before 2015. So taking it literally, 5 years ago from 2018 is 2013, so I'll take that as 0 year. The population was 10,000. Then 2 years later, the population is 2000, so we know what A₀ is and what A(2) is, so based on that, we can solve for k: A(t) = A₀e^(kt) 2000 = 10000e^(k * 2) 0.2 = e^(2k) Natural log of both sides: ln(0.2) = 2k k = ln(0.2) / 2 So now that we know what k is, we can put that into our generation equation to get: A(t) = A₀e^(kt) A(t) = A₀e^(t ln(0.2) / 2) And again, we know what A₀ is, so: A(t) = 10000e^(t ln(0.2) / 2) Now we have a function with only one variable. We are asked to find what year will be when the population is 500. So set A(t) = 500 and solve for t: 500 = 10000e^(t ln(0.2) / 2) 0.05 = e^(t ln(0.2) / 2) Natural log of both sides: ln(0.05) = t ln(0.2) / 2 Multiply both sides by 2 / ln(0.2): 2 ln(0.05) / ln(0.2) = t Now we can use a calculator to get estimations for the logs above to get a decimal approximation for t: t = 3.7227 So it happens before t = 4. When t = 4 the year would be 2017 since when t = 0 the year was 2013. So the population will drop to 500 in the year 2016. If the assumption of t = 0 being 2013 is wrong, then we'll get different answers.
    5 answers · Mathematics · 1 day ago
  • Can someone explain how to do this? Find b such that f(x)=-4x+bx+3 has a maximum value of 50?

    Seems to be a few different answers, so I'll give it a try. I assume you have: f(x) = -4x² + bx + 3 We want the maximum to be 50. So that means that the x that gives us 50 has to be the same x that gives us f'(x) = 0 So first, let's find the first derivative: f'(x) = -8x + b We want this to be zero, so we can solve for x in... show more
    Seems to be a few different answers, so I'll give it a try. I assume you have: f(x) = -4x² + bx + 3 We want the maximum to be 50. So that means that the x that gives us 50 has to be the same x that gives us f'(x) = 0 So first, let's find the first derivative: f'(x) = -8x + b We want this to be zero, so we can solve for x in terms of b: 0 = -8x + b 8x = b x = b/8 Now let's go back to our original function and set f(x) = 50: f(x) = -4x² + bx + 3 50 = -4x² + bx + 3 0 = -4x² + bx - 47 We now have two equations and two unknowns. We have x in terms of b, so we can substitute that into the other equation and then solve for b: 0 = -4(b/8)² + b(b/8) - 47 we get: 0 = -4(b²/64) + b²/8 - 47 0 = -b²/16 + b²/8 - 47 Let's multiply both sides by 16 to get rid of the fractions: 0 = -b² + 2b² - 752 Simplify further: 0 = b² - 752 Solving for b: 752 = b² b = ±√752 b = ±√(16 * 47) b = ± 4√74 You have two values that will give a maximum value of 50 for this function.
    3 answers · Mathematics · 2 days ago
  • Can you play F.E.A.R 2 Project Origin on Mac?

    Natively, it isn't available on the mac. It sounds like it can be run through a wrapper that would make it run on a mac. Info on that is here: http://portingkit.com/game/496 But since Steam doesn't have the game shown as Mac compatible, you won't be able to download the game through the steam client on a mac.
    Natively, it isn't available on the mac. It sounds like it can be run through a wrapper that would make it run on a mac. Info on that is here: http://portingkit.com/game/496 But since Steam doesn't have the game shown as Mac compatible, you won't be able to download the game through the steam client on a mac.
    2 answers · Video & Online Games · 2 days ago
  • When will Nintendo release an actual brand new Mario kart game for the Switch?

    Best answer: If they do, it won't be any time soon. If they do at all. There are improvements in the Deluxe version over the original Wii U version, so it isn't simply "the same game". But what you could do in the Wii U version is here, with more content.
    Best answer: If they do, it won't be any time soon. If they do at all. There are improvements in the Deluxe version over the original Wii U version, so it isn't simply "the same game". But what you could do in the Wii U version is here, with more content.
    2 answers · Video & Online Games · 2 days ago
  • A toy manufacturer needs a piece of plastic in the shape of a right triangle with the longer leg?

    If we know we are working with right triangles, we can use Pythagorean Theorem: a² + b² = c² We are told the longer leg has to be 3 cm more than the shorter leg, so: b = a + 3 And the hypotenuse is 6 cm more than the shorter leg, so: c = a + 6 If we substitute what we have for b and c, we now have an equation with only one variable so we can... show more
    If we know we are working with right triangles, we can use Pythagorean Theorem: a² + b² = c² We are told the longer leg has to be 3 cm more than the shorter leg, so: b = a + 3 And the hypotenuse is 6 cm more than the shorter leg, so: c = a + 6 If we substitute what we have for b and c, we now have an equation with only one variable so we can solve for a: a² + b² = c² a² + (a + 3)² = (a + 6)² Expand and simplify: a² + a² + 6a + 9 = a² + 12a + 36 2a² + 6a + 9 = a² + 12a + 36 a² - 6a = 27 Let's solve this by completing the square. Adding 9 to both sides (the square of half of a's coefficient): a² - 6a + 9 = 36 And now we can factor and solve for a: (a - 3)² = 36 a - 3 = ±6 a = 3 ± 6 We can't have a negative length, so throwing that out we get: a = 3 + 6 a = 9 cm So all three lengths are: 9 cm, 12 cm, and 15 cm
    3 answers · Mathematics · 2 days ago
  • Minecraft Wii U: Is there a way to get Mods for my game?

    You can't mod the Wii U version of Minecraft.
    You can't mod the Wii U version of Minecraft.
    2 answers · Video & Online Games · 2 days ago
  • Please its urgent trig question!!!?

    We have three right triangles that are all 30-60-90 triangles, so we know that similar sides from any 2 of the 3 will be in ratio of each other. Let's start breaking down the large triangle. We know it's a 30-60-90 triangle with a hypotenuse of 15. Since it's 30-60-90, we know that the small leg is half of the hypotenuse, so: x =... show more
    We have three right triangles that are all 30-60-90 triangles, so we know that similar sides from any 2 of the 3 will be in ratio of each other. Let's start breaking down the large triangle. We know it's a 30-60-90 triangle with a hypotenuse of 15. Since it's 30-60-90, we know that the small leg is half of the hypotenuse, so: x = 15/2 Now we can look at the smaller triangle and do the same thing. We know the hypotenuse, so a must be half of that: a = 15/4
    5 answers · Mathematics · 3 days ago
  • What store can I buy realistic money inside the store not online?

    No store, as that's a crime.
    No store, as that's a crime.
    3 answers · Video & Online Games · 3 days ago
  • Anyone else going to pick up Minecraft on the Nintendo Switch tomorrow?

    Most of the people that I know that wanted Minecraft bought the digital version last year. It will get an update to make it the same version as tomorrow's physical release, so they aren't missing anything for buying it early.
    Most of the people that I know that wanted Minecraft bought the digital version last year. It will get an update to make it the same version as tomorrow's physical release, so they aren't missing anything for buying it early.
    1 answer · Video & Online Games · 3 days ago
  • What is y^4 minus y^3 plus 2y^2 +y minus1 divided by y^3 + 1?

    What is wrong with the answers that you got the first time you asked? https://answers.yahoo.com/question/index...
    What is wrong with the answers that you got the first time you asked? https://answers.yahoo.com/question/index...
    4 answers · Mathematics · 3 days ago
  • EU switch game on US switch?

    You can create a US-based account and play on US servers with the EU version of the game. Note that if you want to buy DLC, you have to buy it on your EU account, using the EU eShop using EU funds since it's the EU version of the game. But once you've bought that, you can go back to the US account to play the game with the purchased DLC. show more
    You can create a US-based account and play on US servers with the EU version of the game. Note that if you want to buy DLC, you have to buy it on your EU account, using the EU eShop using EU funds since it's the EU version of the game. But once you've bought that, you can go back to the US account to play the game with the purchased DLC.
    3 answers · Video & Online Games · 3 days ago
  • Nintendo Switch or ps4 pro? Which would you choose?

    I own both a PS4 (launch model) and a Switch. The last game I played on the PS4 was Final Fantasy XII last year. I've put in about 400 hours of play in the Switch since I bought it. So for me, Switch is the recommendation. But get the system that has the games you want to play. If you're not into DK, Mario, or Zelda, PS4 will probably... show more
    I own both a PS4 (launch model) and a Switch. The last game I played on the PS4 was Final Fantasy XII last year. I've put in about 400 hours of play in the Switch since I bought it. So for me, Switch is the recommendation. But get the system that has the games you want to play. If you're not into DK, Mario, or Zelda, PS4 will probably be your system. And if you don't have a 4K display, don't bother with the Pro. Pro does have benefits for a 1080p display, but I don't think they are worth the extra costs. I would go with the PS4 Slim.
    5 answers · Video & Online Games · 4 days ago
  • Does anybody know when Nintendo's next direct is?

    Best answer: They just had one last week. They rarely give us more than 48 hours (outside of the E3 Directs) before a Direct is released. Most of the time it's only 24 hours notice and there has been one where they didn't announce it at all. The last few years there has been one in early July, a few weeks after E3. If this trend... show more
    Best answer: They just had one last week. They rarely give us more than 48 hours (outside of the E3 Directs) before a Direct is released. Most of the time it's only 24 hours notice and there has been one where they didn't announce it at all. The last few years there has been one in early July, a few weeks after E3. If this trend continues, we can expect another one in about three weeks as well. But just because they've done so in the past doesn't mean they will do so this year.
    2 answers · Video & Online Games · 4 days ago
  • Help, Math Problem Explain what the student did wrong and what is the correct solution?

    When subtracting polynomials, you have to remember that subtraction is the same as adding -1 times the value, so writing the subtraction of polynomials keeping them in their own sets of parenthesis for now, we get: (3x + 3h - 2) - (3x - 2) So if we treat that like you are adding -1 times the binomial: (3x + 3h - 2) + (-1)(3x - 2) Now we can... show more
    When subtracting polynomials, you have to remember that subtraction is the same as adding -1 times the value, so writing the subtraction of polynomials keeping them in their own sets of parenthesis for now, we get: (3x + 3h - 2) - (3x - 2) So if we treat that like you are adding -1 times the binomial: (3x + 3h - 2) + (-1)(3x - 2) Now we can distribute the -1 to get: (3x + 3h - 2) + (-3x + 2) Now we can drop the parenthesis and simplify. The x's and constant terms cancel out leaving: 3x + 3h - 2 - 3x + 2 3h
    4 answers · Mathematics · 4 days ago
  • Can you explain this division? 613 divided by 71?

    You eventually will when you find out that there are 0 71's in 6 and 0 71's in 61. So the next step is to see how many 71's in 613. If you can see it without having to use the zero placeholders, go ahead. Just note that if you end up with a remainder larger than your divisor, you missed a step.
    You eventually will when you find out that there are 0 71's in 6 and 0 71's in 61. So the next step is to see how many 71's in 613. If you can see it without having to use the zero placeholders, go ahead. Just note that if you end up with a remainder larger than your divisor, you missed a step.
    4 answers · Mathematics · 5 days ago