• Given that m and n are digits, what is the sum of the values of m and n such that the five-digit number m6,79n is divisible by 72?Show work.?

    Let's break down 72 to see what the prime factorizations are: 72 = 2³ * 3² So it has to be both divisible by 9 and divisible by 8. Because 1000 is divisible by 8, any number is divisible by 8 if the last 3 digits are divisible by 8. Since we know two digits are 7 and 9, we only have a few values to test to see if this is divisible by 8. ... show more
    Let's break down 72 to see what the prime factorizations are: 72 = 2³ * 3² So it has to be both divisible by 9 and divisible by 8. Because 1000 is divisible by 8, any number is divisible by 8 if the last 3 digits are divisible by 8. Since we know two digits are 7 and 9, we only have a few values to test to see if this is divisible by 8. 792 is the only 3-digit number starting with 79 that is divisible by 8. Therefore n must be 2. Now to be divisible by 9, the sum of the digits must also be divisible by 9. Let's add up what we know and see what we have: m + 6 + 7 + 9 + 2 m + 24 To make this divisible by 9, we need the sum to be 27, so m = 3. Now that we know what m and n are, we can find the sum: m + n 3 + 2 5
    2 answers · Mathematics · 11 hours ago
  • How do I simplify radicals as such?

    √12 / √9 The square root of 9 simplifies itself: √12 / 3 Then we can factor out a 4 from the 12 which then can be pulled out of the square root: √(4 * 3) / 3 2√3 / 3 or: (2/3)√3
    √12 / √9 The square root of 9 simplifies itself: √12 / 3 Then we can factor out a 4 from the 12 which then can be pulled out of the square root: √(4 * 3) / 3 2√3 / 3 or: (2/3)√3
    10 answers · Mathematics · 13 hours ago
  • Should i play minecraft and not play any other game until i finish the entire game and kill all the bosses? Answer before 20.12.2018?

    I don't think that you understand what Minecraft is.
    I don't think that you understand what Minecraft is.
    4 answers · Video & Online Games · 14 hours ago
  • The half-life of cobalt-60 is 5.27 years. approximately how much of a 199 g sample will remain after 20 yrs?

    While there are more streamlined equations knowing it's a half-life equation, I still like to use this general equation for growth/decay problems and work out the constant for myself: a(t) = ae^(kt) Where: a = initial amount (when t = 0) t = time after the initial moment (can be any time frame as long as you are consistent with your times --... show more
    While there are more streamlined equations knowing it's a half-life equation, I still like to use this general equation for growth/decay problems and work out the constant for myself: a(t) = ae^(kt) Where: a = initial amount (when t = 0) t = time after the initial moment (can be any time frame as long as you are consistent with your times -- can't talk minutes and then years in the same problem) k = decay constant So first we need to solve for the decay constant. We can start with any starting amount and then half it with time = 5.27 years, so let's solve for k using these variables: a(5.27) = 0.5 a = 1 That gives us: a(t) = ae^(kt) a(5.27) = 1e^(k * 5.27) 0.5 = e^(5.27k) ln(0.5) = 5.27k k = ln(0.5) / 5.27 so now our equation becomes: a(t) = ae^(kt) a(t) = ae^(t ln(0.5) / 5.27) a(t) = ae^(t ln(0.5) / 5.27) So given the initial amount of 199 g, what's left after 20 years? Solve using a = 199 and t = 20: a(t) = 199e^(20 ln(0.5) / 5.27) a(t) = 199e^(20(-0.69315) / 5.27) While I'm rounding here, I'm not in my calculator to reduce errors due to rounding: a(t) = 199e^(-13.86294 / 5.27) a(t) = 199e^(-2.63054) a(t) = 199(0.07204) a(t) = 14.336 g (rounded to 3DP) will remain after 20 years. As a quick estimate, 20 years is a little less than 4 half-lives, so if we half the initial amount 4 times we will have something close: 199 / 2 = 99.5 99.5 / 2 = 49.75 49.75 / 2 = 24.875 24.875 / 2 = 12.4375 They are reasonably close, so we can be confident in the calculated result, which again was: 14.336 g
    4 answers · Mathematics · 15 hours ago
  • Gamer challenge?

    Pong
    Pong
    3 answers · Video & Online Games · 16 hours ago
  • Need help with this math words problem How much money did Carla take out of the bank?

    Best answer: Look at smaller numbers: From 1-5 is obviously 5 numbers. But if you subtract them you get 4. When subtracting numbers, the original number gets counted but the top number doesn't, so you have to add 1 to it to count that missed number.
    Best answer: Look at smaller numbers: From 1-5 is obviously 5 numbers. But if you subtract them you get 4. When subtracting numbers, the original number gets counted but the top number doesn't, so you have to add 1 to it to count that missed number.
    3 answers · Mathematics · 17 hours ago
  • Is it possible for me to get an A in this class if i get an A on the final? (my current grades by category are below)?

    Let's see what we get. Using the break-down you provided as weights we can weight each grade using the final as an unknown and see what is needed to get a 90 overall: 0.15 * 77.59 + 0.1 * 44.44 + 0.05 * 88 + 0.3 * 90 + 0.1 * 100 + 0.3x = 90 11.6385 + 4.444 + 4.4 + 27 + 10 + 0.3x = 90 57.4825 + 0.3x = 90 0.3x = 32.5175 x = 32.5175 / 0.3 x =... show more
    Let's see what we get. Using the break-down you provided as weights we can weight each grade using the final as an unknown and see what is needed to get a 90 overall: 0.15 * 77.59 + 0.1 * 44.44 + 0.05 * 88 + 0.3 * 90 + 0.1 * 100 + 0.3x = 90 11.6385 + 4.444 + 4.4 + 27 + 10 + 0.3x = 90 57.4825 + 0.3x = 90 0.3x = 32.5175 x = 32.5175 / 0.3 x = 108.392 So unless you can get over 108% on the final, you cannot get an A.
    4 answers · Mathematics · 1 day ago
  • Where can I find the game everquest for PC that's relatively cheap? Does it come on any other platform?

    You can download the game client from everquest.com and play up to I think Level 85 for free. After that you have to pay for their All-Access (about $15 a month?) to continue past that. The game is for Windows, only. I believe that the free content is only the base game before any expansions (the 25th expansion just launched the other day). If... show more
    You can download the game client from everquest.com and play up to I think Level 85 for free. After that you have to pay for their All-Access (about $15 a month?) to continue past that. The game is for Windows, only. I believe that the free content is only the base game before any expansions (the 25th expansion just launched the other day). If you choose to buy the latest expansion, you get all previous expansions with it.
    1 answer · Video & Online Games · 1 day ago
  • How do you rationalize the expression?

    I think you mean: (5√2 - 2√5) / (√2 - √5) To rationalize the denominator, multiply both halves by the denominator's conjugate which is (√2 + √5): (5√2 - 2√5)(√2 + √5) / [(√2 - √5)(√2 + √5)] Now expand both halves. The denominator will be rational at the end: (5 * 2 + 5√10 - 2√10 - 2 * 5) / (2 + √10 - √10 - 5) (10 + 5√10 - 2√10 - 10) / (2... show more
    I think you mean: (5√2 - 2√5) / (√2 - √5) To rationalize the denominator, multiply both halves by the denominator's conjugate which is (√2 + √5): (5√2 - 2√5)(√2 + √5) / [(√2 - √5)(√2 + √5)] Now expand both halves. The denominator will be rational at the end: (5 * 2 + 5√10 - 2√10 - 2 * 5) / (2 + √10 - √10 - 5) (10 + 5√10 - 2√10 - 10) / (2 + √10 - √10 - 5) (5√10 - 2√10) / (2 - 5) (3√10) / (-3) Cancel out the 3's and move the negative to the numerator: (√10) / (-1) -√10 Which is oddly enough the same problem I solved 4 days ago and got the same answer: https://answers.yahoo.com/question/index...
    2 answers · Mathematics · 1 day ago
  • An aluminum company has hired you to design a cylindrical can. You are given expressions for both the radius, (5-x)cm, and the height, (2x+1?

    Volume of a cylinder is: V = πr²h You are given an expression for radius and height as: r = 5 - x h = 2x + 1 The radius has to be greater than zero, so x must be smaller than 5. The height must be greater than zero, so x must be larger than -1/2. So the domain restrictions are: -1/2 < x < 5 If we substitute both expressions into the... show more
    Volume of a cylinder is: V = πr²h You are given an expression for radius and height as: r = 5 - x h = 2x + 1 The radius has to be greater than zero, so x must be smaller than 5. The height must be greater than zero, so x must be larger than -1/2. So the domain restrictions are: -1/2 < x < 5 If we substitute both expressions into the volume equation we will have volume in terms of x: V = πr²h V = π(5 - x)²(2x + 1) Simplify: V = (25 - 10x + x²)(2x + 1)π V = (50x + 25 - 20x² - 10x + 2x³ + x²)π V = (40x + 25 - 19x² + 2x³)π V = (2x³ - 19x² + 40x + 25)π Now here is where I'm not sure how to find the max value without using calculus. If this was a quadratic we could do it, but not sure about a cubic. So maybe someone else will have an idea on how to do that. So I can find the "x" needed to get a maximum Volume by solving for the zero of the first derivative knowing the limits of x as explained above. I'll distribute π to every term and treat it as part of the coefficients as a constant (because it is): V = 2πx³ - 19πx² + 40πx + 25π First derivative: V' = 6πx² - 38πx + 40π Solve for zero: 0 = 6πx² - 38πx + 40π First I'll divide both sides by 2π to simplify. Then I'll use the quadratic equation: 0 = 3x² - 19x + 20 x = [ -b ± √(b² - 4ac)] / (2a) x = [ -(-19) ± √((-19)² - 4(3)(20))] / (2 * 3) x = [ 19 ± √(361 - 240)] / 6 x = [ 19 ± √(121)] / 6 x = (19 ± 11) / 6 x = 8/6 and 30/6 x = 4/3 and 5 Since we know that x must be smaller than 5 we can throw that out: x = 4/3 So at x = 4/3, the volume is at a maximum: V = (2x³ - 19x² + 40x + 25)π V = [2(4/3)³ - 19(4/3)² + 40(4/3) + 25]π V = [2(64/27) - 19(16/9) + 40(4/3) + 25]π V = (128/27 - 304/9 + 160/3 + 25)π V = (128/27 - 912/27 + 1440/27 + 675/27)π V = (1331/27)π cm³ or approx: 154.87 cm³ (rounded to 2DP)
    5 answers · Mathematics · 1 day ago
  • Find terms of an arithmetic series?

    I use this expression as the general form for the n'th term of an arithmetic sequence: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. The sum of the first "n" terms of a sequence is the sum of the first and last terms, multiplied by the number of terms, divided by 2, or: S(n) = [a + a(n)]n /... show more
    I use this expression as the general form for the n'th term of an arithmetic sequence: a(n) = a + b(n - 1) Where a is the first term and b is the common difference. The sum of the first "n" terms of a sequence is the sum of the first and last terms, multiplied by the number of terms, divided by 2, or: S(n) = [a + a(n)]n / 2 Let's substitute the a(n) expression here and simplify: S(n) = [a + a + b(n - 1)]n / 2 S(n) = (2a + bn - b)n / 2 S(n) = (2an + bn² - bn) / 2 We are told that S(10) = 210 and S(20) = 820. So using the equation above, substitute what we know and we'll get a system of two equations and two unknowns (a and b) that we can solve for: S(n) = (2an + bn² - bn) / 2 S(10) = (2a * 10 + b * 10² - b * 10) / 2 and S(20) = (2a * 20 + b * 20² - b * 20) / 2 S(10) = (20a + 100b - 10b) / 2 and S(20) = (40a + 400b - 20b) / 2 S(10) = (20a + 90b) / 2 and S(20) = (40a + 380b) / 2 S(10) = 10a + 45b and S(20) = 20a + 190b Now we can substitute the values for S(10) and S(20) and simplify: 210 = 10a + 45b and 820 = 20a + 190b Solve the first equation for a in terms of b, then substitute: 210 = 10a + 45b 210 - 45b = 10a 21 - 4.5b = a 820 = 20a + 190b 820 = 20(21 - 4.5b) + 190b 820 = 420 - 90b + 190b 400 = 100b b = 4 Now we can solve for a: a = 21 - 4.5b a = 21 - 4.5(4) a = 21 - 18 a = 3 Now we know the first term is 3 and the common difference is 4. So the first 5 terms are: 3, 7, 11, 15, 19
    5 answers · Mathematics · 1 day ago
  • Find f. f ''(x) = −2 + 30x − 12x2, f(0) = 8, f '(0) = 18?

    You are told the following: f"(x) = -2 + 30x - 12x² f(0) = 8 f'(0) = 18 As you integrate the double-derivative function to find the original function you generate new constant terms that are initially known. The second two parts pretty much tell you what those constants are. So first, I'm going to put that function into standard... show more
    You are told the following: f"(x) = -2 + 30x - 12x² f(0) = 8 f'(0) = 18 As you integrate the double-derivative function to find the original function you generate new constant terms that are initially known. The second two parts pretty much tell you what those constants are. So first, I'm going to put that function into standard polynomial order, then integrate twice to get the original function: f"(x) = -12x² + 30x - 2 For each term, I'll add 1 to the exponent, divide the coefficient by the new exponent to get the new coefficient then add the constant term at the end: f'(x) = -4x³ + 15x² - 2x + k Since we were told that f'(0) = 18, we know that's what k is: f'(x) = -4x³ + 15x² - 2x + 18 Now do this one more time: f(x) = -x⁴ + 5x³ - x² + 18x + k And again, f(0) = 8, so: f(x) = -x⁴ + 5x³ - x² + 18x + 8 That's your function.
    3 answers · Mathematics · 1 day ago
  • I have the code, where do I show it?

    code for what? You probably don't want to show it anywhere publically so no one else takes it and uses it before you can.
    code for what? You probably don't want to show it anywhere publically so no one else takes it and uses it before you can.
    3 answers · Video & Online Games · 1 day ago
  • Why have many websites enabling listening to internet radio stations been removed?

    Best answer: It's probably got more to do with that there is no way to monetize it so sites that use to run them get taken down due to lack of funding.
    Best answer: It's probably got more to do with that there is no way to monetize it so sites that use to run them get taken down due to lack of funding.
    5 answers · Programming & Design · 1 day ago
  • Where Do I Get a Server From?

    A server is just a computer with software running on it with the intent to accept network connections from a different computer's client software. Server hardware is usually geared more for processor power and memory, but any computer can run server software. So you'll have to be more specific as to what type of server you are wanting? show more
    A server is just a computer with software running on it with the intent to accept network connections from a different computer's client software. Server hardware is usually geared more for processor power and memory, but any computer can run server software. So you'll have to be more specific as to what type of server you are wanting?
    3 answers · Video & Online Games · 1 day ago
  • Do I need to update Super Smash Brothers Ultimate before playing for the first time?

    You will have to update before you can go online, but if you're in the air and won't have online anyway, you'll be able to play single-player just fine with what's on-cart.
    You will have to update before you can go online, but if you're in the air and won't have online anyway, you'll be able to play single-player just fine with what's on-cart.
    3 answers · Video & Online Games · 1 day ago
  • Solve the triangles with the given parts using Law of Sines:?

    Best answer: Law of sines says that the ratio between a triangle's length over the sine of the opposite angle is constant for all sides/angles in the triangle, or: a / sin(A) = b / sin(B) = c / sin(C) Where length "a" and angle "A" are opposites, etc. So we can start with the known length of 52 and opposite angle of 93° to... show more
    Best answer: Law of sines says that the ratio between a triangle's length over the sine of the opposite angle is constant for all sides/angles in the triangle, or: a / sin(A) = b / sin(B) = c / sin(C) Where length "a" and angle "A" are opposites, etc. So we can start with the known length of 52 and opposite angle of 93° to set up the first ratio of the known angle 14° and the unknown opposite length: a / sin(A) = b / sin(B) 52 / sin(93) = b / sin(14) Solve for b by multiplying both sides by sin(14): 52sin(14) / sin(93) = b b ≈ 12.60 (rounded to 2 DP) We don't know length "c" or angle "C" (yet). Since we know two angles and know that the sum of all three angles must be 180°, we can solve for C: A + B + C = 180 93 + 14 + C = 180 107 + C = 180 C = 73° Now that we know C, we can solve for c the same way we solved for b: a / sin(A) = c / sin(C) 52 / sin(93) = c / sin(73) 52 sin(73) / sin(93) = c c ≈ 49.80 (rounded to 2 DP) So your three missing pieces are: b ≈ 12.60 units c ≈ 49.80 units C = 73°
    3 answers · Mathematics · 2 days ago
  • Math words problem help?

    Best answer: Each week the amount doubles. This is a geometric sequence. The general form for this is: a(n) = ab^(n - 1) where a = 1 and b = 2, so: a(n) = 2^(n - 1) The sum of the first n terms of a geometric sequence is: S(n) = a(1 - b^n) / (1 - b) Again, a = 1 and b = 2, so: S(n) = (1 - 2^n) / (1 - 2) S(n) = (1 - 2^n) / (-1) S(n) = 2^n -... show more
    Best answer: Each week the amount doubles. This is a geometric sequence. The general form for this is: a(n) = ab^(n - 1) where a = 1 and b = 2, so: a(n) = 2^(n - 1) The sum of the first n terms of a geometric sequence is: S(n) = a(1 - b^n) / (1 - b) Again, a = 1 and b = 2, so: S(n) = (1 - 2^n) / (1 - 2) S(n) = (1 - 2^n) / (-1) S(n) = 2^n - 1 Solve for n = 10: S(n) = 2^10 - 1 S(n) = 1024 - 1 S(n) = 1023 So 1023 p was saved up after 10 weeks. Why he gave up? Each week would more than double the saved amount every week. The next week would be 1024 resulting in a total of 2047. The week after that would add 2048 for a total of 4095, etc. In a few weeks after that, I'm sure he'd be unable to save the required amount.
    3 answers · Mathematics · 2 days ago
  • Can anyone help me with this math problem? (question in description)?

    Looking at the profit values, we look at the differences of each value and the next: 7 - 11 = -4 11 - 23 = -12 23 - 49 = -26 49 - 95 = -46 95 - 167 = -72 The goal is to get the differences to be the same (or as close as possible). We don't have that, so we repeat the process until we do: -4 - (-12) = -4 + 12 = 8 -12 - (-26) = -12 + 26 =... show more
    Looking at the profit values, we look at the differences of each value and the next: 7 - 11 = -4 11 - 23 = -12 23 - 49 = -26 49 - 95 = -46 95 - 167 = -72 The goal is to get the differences to be the same (or as close as possible). We don't have that, so we repeat the process until we do: -4 - (-12) = -4 + 12 = 8 -12 - (-26) = -12 + 26 = 14 -26 - (-46) = -26 + 46 = 20 -46 - (-72) = -46 + 72 = 26 one more time: 8 - 14 = -6 14 - 20 = -6 20 - 26 = -6 Now they are the same after we did this three times so we know this is a third-degree polynomial so our general form is: p = at³ + bt² + ct + d We know 6 points, but just need 4 of them to create a system of four equations and four unknowns to solve for a, b, c, and d to create our equation, then we can solve for p when t = 10: p = at³ + bt² + ct + d 7 = a(1)³ + b(1)² + c(1) + d and 11 = a(2)³ + b(2)² + c(2) + d and 23 = a(3)³ + b(3)² + c(3) + d and 49 = a(4)³ + b(4)² + c(4) + d 7 = a + b + c + d and 11 = 8a + 4b + 2c + d and 23 = 27a + 9b + 3c + d and 49 = 64a + 16b + 4c + d Solve the first for d in terms of a, b, and c then substitute into the other three: 7 - a - b - c = d 11 = 8a + 4b + 2c + d and 23 = 27a + 9b + 3c + d and 49 = 64a + 16b + 4c + d 11 = 8a + 4b + 2c + 7 - a - b - c and 23 = 27a + 9b + 3c + 7 - a - b - c and 49 = 64a + 16b + 4c + 7 - a - b - c 4 = 7a + 3b + c and 16 = 26a + 8b + 2c and 42 = 63a + 15b + 3c Do the same with solving for c, then substitute: 4 = 7a + 3b + c 4 - 7a - 3b = c 16 = 26a + 8b + 2c and 42 = 63a + 15b + 3c 16 = 26a + 8b + 2(4 - 7a - 3b) and 42 = 63a + 15b + 3(4 - 7a - 3b) 16 = 26a + 8b + 8 - 14a - 6b and 42 = 63a + 15b + 12 - 21a - 9b 8 = 12a + 2b and 30 = 42a + 6b and one more time: 8 = 12a + 2b 8 - 12a = 2b 4 - 6a = b 30 = 42a + 6b 30 = 42a + 6(4 - 6a) 30 = 42a + 24 - 36a 6 = 6a a = 1 Now we can start working back to solve the others: b = 4 - 6a b = 4 - 6(1) b = 4 - 6 b = -2 c = 4 - 7a - 3b c = 4 - 7(1) - 3(-2) c = 4 - 7 + 6 c = 3 d = 7 - a - b - c d = 7 - 1 - (-2) - 3 d = 7 - 1 + 2 - 3 d = 5 So your equation is: p = at³ + bt² + ct + d p = t³ - 2t² + 3t + 5 So now we can solve for p when t = 10: p = 10³ - 2(10)² + 3(10) + 5 p = 1000 - 2(100) + 30 + 5 p = 1000 - 200 + 30 + 5 p = $825
    2 answers · Homework Help · 2 days ago
  • To find the number of inches in 3.5 meters, multiply the number of meters given (3.5) by _____?

    You want to find out how many inches in a meter. So let's start with 1 meter and use conversion factors to turn that into inches: 1 m (100 cm/m) (1/2.54 in/cm) = 100/2.54 in = 39.37 inches per meter (rounded to 2DP)
    You want to find out how many inches in a meter. So let's start with 1 meter and use conversion factors to turn that into inches: 1 m (100 cm/m) (1/2.54 in/cm) = 100/2.54 in = 39.37 inches per meter (rounded to 2DP)
    2 answers · Mathematics · 2 days ago