• How does the number of coils of wire in an electromagnet affect its magnetic strength?

    Best answer: The Magnetic Field Strength is proportional to the Number of Turns of the winding. The basic equation is: Φ ≈ N * I, where Φ is the Flux or Magnetic Field Strength, N is the Number of Turns of the winding and I is the current through the winding. The Magnetic material (the Core) also affects the Flux, but if you keep that constant, then... show more
    Best answer: The Magnetic Field Strength is proportional to the Number of Turns of the winding. The basic equation is: Φ ≈ N * I, where Φ is the Flux or Magnetic Field Strength, N is the Number of Turns of the winding and I is the current through the winding. The Magnetic material (the Core) also affects the Flux, but if you keep that constant, then the Flux will change only according to the Turns and Current. Like the other answerer said; "Provided you do not saturate the Core". See this: http://www.learnabout-electronics.org/ac...
    3 answers · Engineering · 6 years ago
  • A tranformer requires what?

    Alternating Voltage (or Alternating Current, AC). The transformer works on the principle that a voltage is generated in its secondary when an alternating (variable) voltage is applied to its primary. If the applied voltage is Direct Current (DC), there will be NO Voltage present at its secondary.
    Alternating Voltage (or Alternating Current, AC). The transformer works on the principle that a voltage is generated in its secondary when an alternating (variable) voltage is applied to its primary. If the applied voltage is Direct Current (DC), there will be NO Voltage present at its secondary.
    2 answers · Engineering · 6 years ago
  • Why the power is measured in decibel in electronic equipment?

    dB = 10 * log(Power-out / Power-in); this would be the Power Gain of an amplifier for instance. Example: an amp has an input resistance of 10kΩ and 1 volt is applied to it. The Power-in would be V^2 / R = 1^2 / 10k = 0.0001 Watts. With that input the Power out would be, for instance, 100 Watts on an 8Ω load. The Power Gain would be dB = 10 * log(100... show more
    dB = 10 * log(Power-out / Power-in); this would be the Power Gain of an amplifier for instance. Example: an amp has an input resistance of 10kΩ and 1 volt is applied to it. The Power-in would be V^2 / R = 1^2 / 10k = 0.0001 Watts. With that input the Power out would be, for instance, 100 Watts on an 8Ω load. The Power Gain would be dB = 10 * log(100 / 0.0001) = 10 * log(1,000,000) = 10 * 6 = 60 dB. Taken from http://en.wikipedia.org/wiki/Gain Power gain, in decibels (dB), is defined by the 10 log rule as follows: Gain = 10 log (Pout/Pin) dB where Pin and Pout are the input and output powers respectively.
    3 answers · Engineering · 6 years ago
  • Where do you throw away the batteries?

    Call City Hall of the city you leave in.
    Call City Hall of the city you leave in.
    3 answers · Other - Electronics · 6 years ago
  • What store sells microphones other than walmart/target/radio shack?

    Best answer: Guitar Center.
    Best answer: Guitar Center.
    4 answers · Other - Electronics · 7 years ago
  • What is the cost per hour on a machine that is 115 volts and 5.4 amps. This is all of the information I have.?

    If you are in the US, then (115 x 5.4 = 621 watts per hour, as Cameron Fisher said). Now you multiply 621 whr (0.621 kwh) times the cost of electricity of about US$0.15/kwh. So if the dehumidifier is ON 24 hrs/day, in one month it would consume 0.621 kwh x $0.15 x 24 hrs x 30 days, or a total of US$67.07. I think you should be entitled to a refund. show more
    If you are in the US, then (115 x 5.4 = 621 watts per hour, as Cameron Fisher said). Now you multiply 621 whr (0.621 kwh) times the cost of electricity of about US$0.15/kwh. So if the dehumidifier is ON 24 hrs/day, in one month it would consume 0.621 kwh x $0.15 x 24 hrs x 30 days, or a total of US$67.07. I think you should be entitled to a refund.
    3 answers · Other - Electronics · 7 years ago
  • Why is the wall outlet zapping when I plug in a cord that is now dry but was wet?

    Try the drier on a different outlet. If it does the same, then your drier is defective, if it works, then there is a problem in the original outlet. To confirm that, plug a lamp or any other device into it.
    Try the drier on a different outlet. If it does the same, then your drier is defective, if it works, then there is a problem in the original outlet. To confirm that, plug a lamp or any other device into it.
    1 answer · Other - Electronics · 7 years ago
  • How to obtain an expression for equivalent resistance when circuit is in series ?

    Series; Rseries = R1+R2+... Parallel: 1 / Rparallel = 1/R1+1/R2+1/...; Rparallel= R1*R2/(R1+R2) Series-Parallel: Combine the two equations.
    Series; Rseries = R1+R2+... Parallel: 1 / Rparallel = 1/R1+1/R2+1/...; Rparallel= R1*R2/(R1+R2) Series-Parallel: Combine the two equations.
    5 answers · Engineering · 7 years ago
  • About Power generation?

    At 20 kwh per day, if the consumption is constant, the power would be 20 kwh/24 h = 0.833 kw (this is 20 kw each hour divide by 24 hours per day), so the capacity of the power plant should be 0.833 kw. Now, if the power is variable during the day, then the capacity would have to be that of the maximum power at any instant.
    At 20 kwh per day, if the consumption is constant, the power would be 20 kwh/24 h = 0.833 kw (this is 20 kw each hour divide by 24 hours per day), so the capacity of the power plant should be 0.833 kw. Now, if the power is variable during the day, then the capacity would have to be that of the maximum power at any instant.
    2 answers · Engineering · 7 years ago
  • Converting 230v 50hz to 110v 60hz?

    Best answer: You can try Digikey.com or Mouser.com. You need a STEP-UP transformer, you are stepping up the 110v (or 115v) in the US outlet to 230v to power the coffee machine. The 50 Hz and 60 Hz in this case does not affect since the coffee machine is probably a resistive load (heater) and most likely does not have motors. It may cost quite a... show more
    Best answer: You can try Digikey.com or Mouser.com. You need a STEP-UP transformer, you are stepping up the 110v (or 115v) in the US outlet to 230v to power the coffee machine. The 50 Hz and 60 Hz in this case does not affect since the coffee machine is probably a resistive load (heater) and most likely does not have motors. It may cost quite a bit. Make sure the transformer can handle the load (Watts) that the machine needs (look into the back-plate of the machine). It should be rated for the same or higher power. The following is an example for a 1000 Watts (VA): http://www.digikey.com/product-detail/en... or http://www.hammondmfg.com/176.htm This transformer is called an Auto-transformer, because the Primary and Secondary windings are connected together. It provides NO isolation. You may also need to buy an adapter to match the plug of the coffee machine. Email me if you need more details.
    1 answer · Other - Electronics · 7 years ago
  • Convertin 230v 50hz to 110v 60hz?

    Look into my answer to your other repeated question.
    Look into my answer to your other repeated question.
    5 answers · Other - Electronics · 7 years ago
  • Can I use a car amplifier for home use to lower energy comsuption?

    For the same power out, meaning you play as loud, the input power will be about the same. This depends on the efficiency of the power supply, most likely converting 120 vac to 12 vdc to power the car amp will be less efficient. Overall, you will not reduce the power consumption. Listen at a lower output power level, this will reduce consumption,... show more
    For the same power out, meaning you play as loud, the input power will be about the same. This depends on the efficiency of the power supply, most likely converting 120 vac to 12 vdc to power the car amp will be less efficient. Overall, you will not reduce the power consumption. Listen at a lower output power level, this will reduce consumption, provided the amp is not a class A.
    5 answers · Home Theater · 7 years ago
  • What is a leveling capacitor?

    Read this article, it'll give you an explanation about leveling capacitors: http://forum.9000rpm.co.za/viewtopic.php...
    Read this article, it'll give you an explanation about leveling capacitors: http://forum.9000rpm.co.za/viewtopic.php...
    2 answers · Other - Electronics · 7 years ago
  • AC wont turn on after power outage?

    One reason could be that the breaker that powers the AC has tripped. Go to the breaker box, check the breakers, see if one or more are OFF. If you see one OFF, flip it fully to the left, then fully to the right.
    One reason could be that the breaker that powers the AC has tripped. Go to the breaker box, check the breakers, see if one or more are OFF. If you see one OFF, flip it fully to the left, then fully to the right.
    2 answers · Other - Electronics · 7 years ago
  • Which countries use electrical plugs that have two flat prongs set at an angle like the sides of triangle?

    Look into this site: http://www.dbicorporation.com/internat/i... Scroll down all the way to see the plug types, find the one you want (take note of the plug #), see the countries that use that #. One example is Plug 6, Argentina.
    Look into this site: http://www.dbicorporation.com/internat/i... Scroll down all the way to see the plug types, find the one you want (take note of the plug #), see the countries that use that #. One example is Plug 6, Argentina.
    5 answers · Other - Electronics · 7 years ago
  • How do you Convert 7.75v to 5v?

    Using a resistor in series to drop 2.75v (7.75-5) has the disadvantage of dissipating the extra power on the resistor and if the load current varies, the 5v will change. It's best to use a DC to DC Converter, but it may be hard to find one that is for those voltages. If you use a resistor, you calculate it as follows: 2.75v/1.6mA = 1,719Ω. The... show more
    Using a resistor in series to drop 2.75v (7.75-5) has the disadvantage of dissipating the extra power on the resistor and if the load current varies, the 5v will change. It's best to use a DC to DC Converter, but it may be hard to find one that is for those voltages. If you use a resistor, you calculate it as follows: 2.75v/1.6mA = 1,719Ω. The power dissipation on the resistor: 2.75*1.6 = 0.0044 watts. Use a 1/4 watt resistor.
    3 answers · Engineering · 7 years ago
  • Are capacitors in a series/parallel comparable to batteries in series/parallel?

    Two (equal) capacitors in parallel will Double the Total Capacitance and will take longer to discharge. Two in series will Double the Total Voltage of the series, but the capacitance will be 1/2 of each. The formula is Q=C V. If you charge the capacitors with a Total Charge: For Equal Total Charge Q, if C doubles, V will be 1/2; if C is 1/2 then... show more
    Two (equal) capacitors in parallel will Double the Total Capacitance and will take longer to discharge. Two in series will Double the Total Voltage of the series, but the capacitance will be 1/2 of each. The formula is Q=C V. If you charge the capacitors with a Total Charge: For Equal Total Charge Q, if C doubles, V will be 1/2; if C is 1/2 then V doubles. This may be difficult to visualize. One additional item related to capacitors is their Reactance (Xc). Xc = 1 /2*π*f*C. This allows you to calculate the time that the capacitor will hold its charge, depending on the value of the resistor used to discharge it.
    6 answers · Engineering · 7 years ago
  • A voltmeter is switches on and it gives a reading of 0.01V even though it isn't attached to anything.?

    Digital Voltmeter Accuracy is specified as a % of the reading +/- 1 digit. If the 1 on 0.01 is the last digit of the display, then that's the =/-1 digit of the accuracy. Or it can be that the meter is detecting a signal. Short the two leads to see if it goes away.
    Digital Voltmeter Accuracy is specified as a % of the reading +/- 1 digit. If the 1 on 0.01 is the last digit of the display, then that's the =/-1 digit of the accuracy. Or it can be that the meter is detecting a signal. Short the two leads to see if it goes away.
    4 answers · Engineering · 7 years ago
  • Need help with Magnetic Reluctance?

    Best answer: R = l / (uo ur A) uo =permeability of air = 4π 10^-7 ur = 4000 (in your case) A (Cross-sectional Area) = 1800 mm^2 (in your case) l (length) = 150 mm (in your case)
    Best answer: R = l / (uo ur A) uo =permeability of air = 4π 10^-7 ur = 4000 (in your case) A (Cross-sectional Area) = 1800 mm^2 (in your case) l (length) = 150 mm (in your case)
    1 answer · Engineering · 7 years ago
  • How to calculate the size of each wire?

    Best answer: It means that each wire has a cross-section (Area) of 25 sq mm. Now Area = π R^2 or π D^2/4. So D = square-root (4*Area / π) D = square-root(4*25/π) = square-root(100/π) = square-root(31.83) =~ 5.36 mm
    Best answer: It means that each wire has a cross-section (Area) of 25 sq mm. Now Area = π R^2 or π D^2/4. So D = square-root (4*Area / π) D = square-root(4*25/π) = square-root(100/π) = square-root(31.83) =~ 5.36 mm
    1 answer · Engineering · 7 years ago