Jacob
- Member since:
- March 01, 2012
- Total points:
- 165 (Level 1)
Can someone please explain this to me?
Ok so i'm 13 and recently learned about imaginary numbers, that i is the square root of -1. I was thinking about this last night and i formulated a proof to say that the square root of -1 is not imaginary and in fact -1.
Here is the proof:
i = SR (square root) of -1
i^2 = -1 (i squared both sides)
-i^2 = 1 (i multiplyed both sides by -1)
-i = 1 (i square rooted both sides)
i = -1 (I multiplyed both sides by -1)
So therefore, the square root of -1 is -1 itself.
P.S: Please don't hesitiate on telling me i'm wrong as i love to learn and i would like to find out why scientists think that i is an imaginary number, if this is true. Thanks for answering!!!
by Anonymou...
- Member since:
- October 19, 2011
- Total points:
- 2,539 (Level 4)
Best Answer - Chosen by Voters
I thought that at first two! The reason i is imaginary is because you can't find the square root of a negative. 1 times 1= 1 and -1 times -1 also equals one because a negative times a negative equals a positive so therefore no number can really = the square root of - 1.
These are correct:
i = SR (square root) of -1
i^2 = -1 (i squared both sides)
-i^2 = 1 (i multiplyed both sides by -1)
These two are incorrect:
-i = 1 (i square rooted both sides)
i = -1 (I multiplyed both sides by -1)
-
by Anonymou...
- Member since:
- October 04, 2011
- Total points:
- 704 (Level 2)
Well first and foremost you cannot take a sqrt of a negative number according to modern mathematics, but what you're saying is that you are...
√-1=i
-1=i²
1=-i²
0=-1-i²
0=0
√-1=i
(√-1)²=(i)²
1=1
Unfortunately this is all assuming that √-1=i
The main question here should be which came first, Roots or Powers?
Because -1²=1
and √(-1²)=√(1)
-1=1 Not true...Even though in theory it would work depending on how you think of it...but eh...The world of mathematics is weird for example: 0/0
Is it 0, 1, Infinity?
But, eh...Whatever.
Why don't you study imaginary numbers and prove to everyone someday that this is so, that in fact √-1=-1
(And unfortunately you can't just do -1√-1=√1=1*-1=-1)
Good luck with your theory.
Source(s):
AP Calculus
-
by nisssanl...
- Member since:
- June 06, 2008
- Total points:
- 311 (Level 2)
You are very smart! Just one little mistake..
on your third step: -i^2 = 1
to your fourth step, there is an error.
Your proof would only work if it was (-i)^2. But no. It is -i^2 meaning the i is the only thing being squared. You look at it like you are taking the square root of a square, but that only works if the square is by itself. It isn't, there is a -1 times to it. That mistake makes the rest of the proof invalid