A student took 5.0 L of 2.0 mol/L Pb(NO3)2(aq) and diluted it by adding 30.0 L of distilled water. How many?

Question

moles of solute are present in the diluted solution?

Answer 1

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I will answer your question as written

the number of moles of solute is 5*2=10 moles

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Answer 2

M1V1 = M2V2

(5.0L)(2.0M) = (35.0L)(X)

X = 0.29 M

moles of solute (diluted) = 0.29 mols /L * 35.0L = 10.0 mols